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Inessa05 [86]
3 years ago
6

What is the length of BC? A. 2.0 B. 2.1 C. 2.55 D. 2.75

Mathematics
2 answers:
Mariulka [41]3 years ago
7 0
I hope this helps you

Arturiano [62]3 years ago
6 0
AB is the hyp
AC is the adj 
BC is the opp. 

You can find the BC by using SOHAHTOA
we need to know the opp and have the adj and an angle.. we can use TAN
so TAN(23) = BC/6 
BC = 6 x Tan(23) 
BC = 2.55 
so the answer's C.
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Write the equation in slope intercept form. Identify the m and b. 3x−3y=−9
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4 years ago
The diagram shows the rectangle ABCD, where A is (3,2) and B is (1,6).
In-s [12.5K]
(i)
A(3,2),B(1,6)
\\
\\m_{AB}= \frac{6-2}{1-3}=-2
\\
\\m_{BC}m_{AB}=-1
\\ 
\\m_{BC}= \frac{-1}{m_{AB}} = \frac{-1}{-2}= \frac{1}{2}  
\\
\\B(1,6)\Rightarrow x_1=1,y_1=6
\\
\\BC:y-y_1=m_{BC}(x-x_1)
\\
\\y-6= \frac{1}{2}(x-1)
\\
\\2y-12=x-1
\\x-2y+11=0

(ii)
AC:y=x-1
\\BC:x-2y+11=0
\\
\\C=AC\cap BC
\\
\\x-2(x-1)+11=0
\\x-2x+2+11=0
\\x=13
\\y=x-1=13-1=12
\\C(13,12)

(iii)
A(3,2)B(1,6),C(13,12)
\\P=2(d(A,B)+d(B,C))
\\
\\d(A,B)= \sqrt{(1-3)^2+(6-2)^2}= \sqrt{20}  =2 \sqrt{5} 
\\
\\d(B,C)= \sqrt{(13-1)^2+(12-6)^2}= \sqrt{180}= 6\sqrt{5}  
\\ 
\\P=2(2 \sqrt{5}+6 \sqrt{5})=2\times8 \sqrt{5} =16 \sqrt{5}
6 0
3 years ago
Explain how 49. 567 is done in fraction form
pav-90 [236]
<span>= 49567/1000

</span>rite the decimal number as a fraction
(over 1)
49.567 = 49.567 / 1

Multiplying by 1 to eliminate 3 decimal places
we multiply top and bottom by 3 10's

Numerator (N)
N = 49.567 × 10 × 10 × 10 = 49567
Denominator (D)
D = 1 × 10 × 10 × 10 = 1000

N / D = 49567 / 1000

Simplifying our fraction

<span>= 49567/1000</span>
7 0
3 years ago
Y=3x-5 identify y intercept within equation
anastassius [24]

Answer: -5

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5 0
4 years ago
Read 2 more answers
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