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3 years ago

Pls help only b,d, and f

Mathematics

1 answer:

Leya [2.2K]3 years ago

8 0

Solving for y right?

2y = 3x + 4 - x
2y = 2x + 4
y = 2x + 4 over 2
y = 2 (x + 2) over 2
y = x + 2

y - 3 = 2x - 6 over 2
y - 3 = 2(x - 3) over 2
y - 3 = x - 3
y = x

x - y - 2 = 2(2x + 1)
-y - 2 = 2(2x + 1) - x
-y = 2(2x + 1) - x + 2
y = -2(2x + 1) + x - 2

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Dmitry_Shevchenko [17]

Answer :-  option 3rd !!

Step-by-step explanation:

∆FGE ~ ∆ JKL

i.e, Angle FGE = angle JKL = 63°

and angle GEF = angle KLJ = 29°

also, angle GFE = angle KJL = 88°

so, the ∆FGE ~ ∆ JKL by AA property of similarity !!

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For eg. for ∆ EFG ~ ∆ JKL

the angle EFG must be equal to angle JKL to be similar !!

but they are not equal !!

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and such ,all other options except 3rd is wrong !!

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