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3 years ago

Please help I put 50 points

Mathematics

2 answers:

olga nikolaevna [1]3 years ago

4 0

Answer:

output = input - equation

y = x - 7

so 7 is your correct equation!!

Step-by-step explanation:

as u can see

When input x is subtracted from output y, we are getting answer 7

like here

imma gonna tell u how 7 is came

1-8=7

2-9=7

3-10=7

4-11=7

so 7 is our equation

its just a explanation okay

so we get our solution

•°• Y = X - 7

hope it may help you!!

mark as brainlist

Yuri [45]3 years ago

3 0

Answer:

y = x+7

Step-by-step explanation:

Assuming all of these numbers are ordered pairs (coordinates) when x is 1 y is 8, when x is 2 y is 9 and so on. If you notice y is going up by 1 every time so it follows that the starting point (y intercept) must be 7. Therefore, our equation will be y = x + 7.

Test it out:

Let x =2

y = 2 + 7 = 9 This matches our coordinate (2,9) so it's correct.

Let x =4

y = 4 + 7 = 11 This matches our coordinate (4,11) so it's correct.

Feel free to try out the rest of the coordinates, but usually 2 is enough to confirm that your equation is correct.

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4x – 1 = 7x – 16 Solve the problem (Show your work)

Katarina [22]

Answer:

x = 5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define equation

4x - 1 = 7x - 16

Step 2: Solve for x

Subtract 4x on both sides: -1 = 3x - 16
Add 16 to both sides: 15 = 3x
Divide 3 on both sides: 5 = x
Rewrite: x = 5

Step 3: Check

Plug in x into the original equation to verify it's a solution.

Substitute in x: 4(5) - 1 = 7(5) - 16
Multiply: 20 - 1 = 35 - 16
Subtract: 19 = 19

Here we see that 19 does indeed equal 19.

∴ x = 5 is a solution to the equation.

6 0

3 years ago

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0.441 to its standard form

vlada-n [284]

Answer:

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Step-by-step explanation:

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8 0

3 years ago

Find a particular solution to the differential equation y′′+2y′+y=2t2−t+3e−2t. y′′+2y′+y=2t2−t+3e−2t.

Jlenok [28]

$y''+2y'+y=2t^2-t+3e^{-2t}$

The characteristic equation is

$r^2+2r+1=(r+1)^2=0\implies r=-1$

so the characteristic solution is

$y_c=C_1e^{-t}+C_2te^{-t}$

For the particular solution, we can try looking for a solution of the form

$y_p=at^2+bt+c+de^{-2t}$
$\implies{y_p}'=2at+b-2de^{-2t}$
$\implies{y_p}''=2a+4de^{-2t}$

Substituting into the ODE, we have

$(2a+4de^{-2t})+2(2at+b-2de^{-2t})+(at^2+bt+c+de^{-2t})=2t^2-t+3e^{-2t}$
$at^2+(4a+b)t+(2a+2b+c)+de^{-2t}=2t^2-t+3e^{-2t}$
$\implies\begin{cases}a=2\\4a+b=-1\\2a+2b+c=0\\d=3\end{cases}\implies a=2,b=-9,c=14,d=3$

So the general solution to the ODE is

$y=y_c+y_p$
$y=C_1e^{-t}+C_2te^{-t}+2t^2-9t+14+3e^{-2t}$

4 0

3 years ago

Horatio was gazing into the night from his bedroom window. he was watching for aliens

kotykmax [81]

Answer:

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Step-by-step explanation:

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2 years ago

HELP ASAP

Setler79 [48]

Answer:

Step-by-step explanation:

Please mark me brainlist

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3 years ago