Please help photo attached

Solve the equation by using the Square Root Property. 16x2 + 16x + 4 = 81

Maslowich

Answer:

$x = \dfrac{7}{4}, x = \dfrac{-11}{4}$

Step-by-step explanation:

We are given the following equation in the question:

$16x^2 + 16x + 4 = 81$

We have to find the solution of the equation using square root property.

We can solve the equation as:

$16x^2 + 16x + 4 = 81\\(4x)^2 + 2(4x)(2) + (2)^2 = 81\\\text{Identity: }(a+b)^2 = a^2 + b^2 + 2ab\\\Rightarrow (4x+2)^2 = 81\\ \Rightarrow (4x+2) = \sqrt{81}\\ \Rightarrow (4x+2) = \pm 9\\ \Rightarrow (4x+2) = 9, (4x+2) = -9\\\Rightarrow 4x = 7, 4x = -11\\\Rightarrow x = \dfrac{7}{4}, x = \dfrac{-11}{4}$

is the required solution of the equation.

6 0

3 years ago

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

2 years ago

Where do I put the other two

Ilya [14]

You can put h on -1 and sum on 0.4. Also, you put 1.4 in the wrong place. It should be three more places to the right.

4 0

3 years ago

Jimmy works part-time at Walmart earning $11 per hour. He is allowed to work anywhere between 0 to 30 hours per week. His only e

Mashcka [7]

The answer is letter A.

8 0

2 years ago

I need help with these 2

Slav-nsk [51]

Answer:

Step-by-step explanation: Hey for the second one I got y = -3/4x -0.5 I'm not sure if its correct though sorry if not
ill try my best to explain my solution though
1. From the parallel equation (3x + 4y = 12) all we need to do is find the slope

So the easiest way to do so is to put the said equation in y-intercept form

y=mx +b
m= slope

b= y intercept

so 1. 3x + 4y = 12

=

4y = 12-3x

divide that by 4 to get only y

y=3-3/4x

-3/4 is our slope

y=-3/4x+b

than we have a point -2, -2

if we put -2 for y

-2=-3/4x+b

and then we put our -2 for x
-2 = -3/4 * -2 + b

=

-2 = -1.5 +b
b=-0.5

Answer : y=-3/4x-0.5

4 0

1 year ago