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3 years ago

Can someone help me asap?????

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

6 0

The answer is 175.45

Surface area of a cone = πrs + πr2
Volume of a cone = 1/3πr2h.
The slant of a right circle cone can be figured out using the Pythagorean Theorem if you have the height and the radius.
Answers for volume problems should always be in cubic units.

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You lose an online auction for an autograph. Your losing bid of $28 is 40% of the winning bid. How much less was your bid than t

TEA [102]

Answer:

My bid was $42 less than the winning bid.

Step-by-step explanation:

The winning bid is x.

$28 is 40% of x

0.4x = 28

x = 28/0.4

x = 70

The winning bid was $70.

$70 - $28 = $42

Answer: My bid was $42 less than the winning bid.

5 0

3 years ago

Determine the intercepts of the line 2x+5y=-6?

SVETLANKA909090 [29]

Answer:

The x intercept is (-3,0)

The y intercept is (0,-6/5)

Step-by-step explanation:

To find the x intercept, set y =0 and solve for x

2x+5y=-6

2x+0 = -6

Divide by 2

2x/2 = -6/2

x = -3

The x intercept is (-3,0)

To find the y intercept, set x =0 and solve for y

2x+5y=-6

0+5y = -6

Divide by 5

5y/5 = -6/5

y = -6/5

The y intercept is (0,-6/5)

7 0

3 years ago

Yesterday I drank 16 cups of coffee. Today I drank 82% more cups. How many cups of coffee did I drink today?

sashaice [31]

Answer: 29.12 cups of coffee

Step-by-step explanation:

16 cups of coffee x 0.82 = 13.12

13.12 + 16 = 29.12

3 0

3 years ago

at the picnic Grove birdwatcher saw 42 Robin's looking for worms if they were five times as many starlings as Robins how many st

labwork [276]

There were 210 starlings, just multiply 42 by 5.

3 0

4 years ago

Uppose y(t)=9e−5t

adoni [48]

If $y(t)=9e^{-5t}$ satisfies the ODE $y'-ky=0$ , then

$y'(t)=-45e^{-5t}$

and substituting into the ODE gives

$-45e^{-5t}-9ke^{-5t}=0\implies k=-5$

so that the ODE is $y'+5y=0$ .

I'm assuming that you're also supposed to determine the initial value $y_0$ given this ODE. You have

$y'+5y=0\implies e^{5t}y'+5e^{5t}y=0\implies(e^{5t}y)'=0\implies e^{5t}y=C\implies y=Ce^{-5t}$

Given $y(0)=y_0$ , you have

$y_0=C$

but since you already know that $y=9e^{-5t}$ , it follows that $C=9$ , and in turn that $y_0=9$ .

5 0

3 years ago