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KiRa [710]
3 years ago
11

What is two-thirds divided by 10? (will give brainliest)

Mathematics
2 answers:
KiRa [710]3 years ago
7 0

Answer:

1/15

Step-by-step explanation:

maks197457 [2]3 years ago
6 0

Answer:

0.66

Step-by-step explanation:

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Whats the point slope of y+1=2/3(x-4)
Harlamova29_29 [7]
The slope is also known as x or m, and therefore, the slope is 2/3x in this equation.
7 0
3 years ago
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If the measurement a is 69 and measurement a and b are complementary what is measurement b
MA_775_DIABLO [31]

Answer:

nice and

since it is complementary then a +b = 90

and substitution gives

69 + b = 90

b = 21

hope this helped and brainliest pls

4 0
3 years ago
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The results of an election are shown in the table below.
vazorg [7]

We are given the results of an election:

Candidate Fraction of votes

Johnson = \frac{1}{9}

Smith  = \frac{7}{18}

Dragovic = \frac{1}{2}

Now, we need to find the difference between the fractions of votes received by Dragovic and Johnson.

Therefore, difference is :

\frac{1}{2} - \frac{1}{9}

Taking common denominator of 2 and 9 is 18.

=\frac{1\times9}{2\times 9} - \frac{1\times 2}{9\times 2}

=\frac{9}{18} - \frac{2}{18}

=\frac{9-2}{18}

=\frac{7}{18}

Therefore, the difference between the fractions of votes received by Dragovic and Johnson is \frac{7}{18}.


4 0
3 years ago
A random sample of 77 fields of durum wheat has a mean yield of 27.427.4 bushels per acre and standard deviation of 5.755.75 bus
xz_007 [3.2K]

Answer:

[ 21.79, 33.0 ]

Step-by-step explanation:

Given:

Sample size, n = 7

Sample mean, μ = 27.4

Standard deviation, σ = 5.75

Confidence level is 99%

also, population is normal i.e normally distributed

Thus,

Confidence interval = μ ± z\frac{\sigma}{\sqrt n}

For confidence level of 99%

z-value = 2.58

Therefore,

Lower limit of Confidence interval = μ - 2.58\times\frac{5.75}{\sqrt{7}}

or

Lower limit of Confidence interval = 27.4 - 2.58\times\frac{5.75}{\sqrt{7}}

or

Lower limit of Confidence interval = 21.79

Upper limit of Confidence interval = μ + 2.58\times\frac{5.75}{\sqrt{7}}

or

Upper limit of Confidence interval = 27.4 + 2.58\times\frac{5.75}{\sqrt{7}}

or

Upper limit of Confidence interval = 33.00

Hence, confidence interval = [ 21.79, 33.0 ]

5 0
3 years ago
Help me please thank you
grin007 [14]
2 3/4 - 1 = 1 3/4 or 1.75
5 0
3 years ago
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