What is 69/25 as a terminating decimal

Find the Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables. If x = f(u, v, w), y = g(u, v, w), and z = h(u, v

jeyben [28]

Answer:

The Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables

= -3072uv

Step-by-step explanation:

Step :-(i)

Given x = 1 6 (u + v) …(i)

Differentiating equation (i) partially with respective to 'u'

$\frac{∂x}{∂u} = 16(1)+16(0)=16$

Differentiating equation (i) partially with respective to 'v'

$\frac{∂x}{∂v} = 16(0)+16(1)=16$

Differentiating equation (i) partially with respective to 'w'

$\frac{∂x}{∂w} = 0$

Given y = 1 6 (u − v) …(ii)

Differentiating equation (ii) partially with respective to 'u'

$\frac{∂y}{∂u} = 16(1) - 16(0)=16$

Differentiating equation (ii) partially with respective to 'v'

$\frac{∂y}{∂v} = 16(0) - 16(1)= - 16$

Differentiating equation (ii) partially with respective to 'w'

$\frac{∂y}{∂w} = 0$

Given z = 6uvw ..(iii)

Differentiating equation (iii) partially with respective to 'u'

$\frac{∂z}{∂u} = 6vw$

Differentiating equation (iii) partially with respective to 'v'

$\frac{∂z}{∂v} =6 u (1)w=6uw$

Differentiating equation (iii) partially with respective to 'w'

$\frac{∂z}{∂w} =6 uv(1)=6uv$

Step :-(ii)

The Jacobian ∂(x, y, z)/ ∂(u, v, w) =

$\left|\begin{array}{ccc}16&16&0\\16&-16&0\\6vw&6uw&6uv\end{array}\right|$

Determinant 16(-16×6uv-0)-16(16×6uv)+0(0) = - 1536uv-1536uv

= -3072uv

Final answer:-

The Jacobian ∂(x, y, z)/ ∂(u, v, w) = -3072uv

6 0

3 years ago

Find the average rate of change between f(-7) and f(-1) in the function f(x)=x^2+2x -8

Viktor [21]

Solve the equation by replacing x with -7 and then -1.

Then subtract the two to find the difference and divide that by the difference between -7 and -1.

f(-7) = -7^2 + 2(-7) -8 = 49 -14 -8 = 27

f(-1) = -1^2 + 2(-1) -8 = 1 -2 - 8 = -9

Difference between 27 and -9 = -36

Difference between -1 and -7 = -6

Rate of change = -36 /-6 = 6

3 0

3 years ago

Which is traveling faster, a car whose velocity vector is 201 + 25), or a car whose velocity vector is 30i, assuming that the un

Snowcat [4.5K]

Answer:

2nd car is running faster than the first car by 2.01 units.

Step-by-step explanation:

Let's assume that

the velocity of first car,

$v_1\ =\ 20i\ +\ 25j$

and the velocity of second car

$v_2\ =\ 30i$

=> speed of first car,

$u_1\ =\ \sqrt{(20)^2+(25)^2}$

$=\ \sqrt{400+625}$

$=\ \sqrt{1025}$

= 32.01 units

and speed of second car,

$u_2\ =\ \sqrt{(30)^2+(0)^2}$

= 30 units

$u_2\ -\ u_1\ =\ 32.01\ -30$

= 2.01 units

Hence, 2nd car is running faster than the first car by 2.01 units.

8 0

3 years ago

HELP PLS IM DUM

Andrews [41]

ur not dum

Answer:

Paul

Step-by-step explanation:

Paul earn more than monica. Though he is getting less interest but because of his higher initial amount he is getting more return.

Computing the return of both

Monica return is 100*3.4%= $3.4 in a year

Paul return is 200*%2.2= $4.4 in a year.

5 0

2 years ago

Graph the inequality: –10 < t < 5

shusha [124]

Answer:

no lo sé perdón buen día puto hgfhkghhhddj

Step-by-step explanation:

ñkwbfñxfhñieqehceqifheihifiwhfifhapuxqbepuxbkeqqpcvieqpfbiqepehcioeqbgeigbwgjwlbfiwqfbeiqbwofhwohqohfoqhglqjgpwkgowjfowjfowfu abbdnznznnsksj

ocvjñxhlkzxhllzhzhlcbvg,igxpgofypyfñjguñcñjgjñfodoyfpugpifojvvvbbbbbbbbbbbbbbbnnputo

7 0

3 years ago