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Yuki888 [10]
2 years ago
5

Zack used these steps to solve this equation:

Mathematics
1 answer:
photoshop1234 [79]2 years ago
6 0

Answer:

C. In step 3, he should have divided both sides by  Start Fraction 6 Over 4 End fraction.

Step-by-step explanation:

got it right edge 2021

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A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t)=(t)ln(5t). Find the acceleration of the par
lyudmila [28]

Answer:

a(\frac{1}{5e})=5e

Step-by-step explanation:

we are given equation for position function as

s(t)=tln(5t)

Since, we have to find acceleration

For finding acceleration , we will find second derivative

s'(t)=\frac{d}{dt}\left(t\ln \left(5t\right)\right)

=\frac{d}{dt}\left(t\right)\ln \left(5t\right)+\frac{d}{dt}\left(\ln \left(5t\right)\right)t

=1\cdot \ln \left(5t\right)+\frac{1}{t}t

s'(t)=\ln \left(5t\right)+1

now, we can find derivative again

s''(t)=\frac{d}{dt}\left(\ln \left(5t\right)+1\right)

=\frac{d}{dt}\left(\ln \left(5t\right)\right)+\frac{d}{dt}\left(1\right)

=\frac{1}{t}+0

a(t)=\frac{1}{t}

Firstly, we will set velocity =0

and then we can solve for t

v(t)=s'(t)=\ln \left(5t\right)+1=0

we get

t=\frac{1}{5e}

now, we can plug that into acceleration

and we get

a(\frac{1}{5e})=\frac{1}{\frac{1}{5e}}

a(\frac{1}{5e})=5e


5 0
3 years ago
What is the area in square inches of a rectangle with a length of 6.3 feet, and a width of 2.5 feet? A. 189 in2 B. 141.75 in2 C.
KATRIN_1 [288]
Area of a rectangle is
A=L*W=6.3ft * 2.5ft=15.75 ft^2

we know that 1 ft^2=144 in^2
15.75ft^2*144=2268in^2
6 0
3 years ago
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