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seropon [69]
3 years ago
15

Numbers are (-20,10) and (40,-50)​

Mathematics
1 answer:
seropon [69]3 years ago
6 0
Hdbanwlsksmaakdicjcjdndisisushshsudhehehhs
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Step One

Figure out the actual change.

Change = 2.78 - 2.45

Change = 0.33

Step 2

Find the % change

% Change = 0.33/2.45 * 100 = 13.5%


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Point A is at (4,5) and lies on the graph of quadratic function f. If g(x)=f(2x), determine the location of this point on the gr
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\bf \stackrel{f(x)}{(\stackrel{x}{4}~~,~~\stackrel{y}{5})}\qquad \qquad \qquad \stackrel{g(x)}{(\stackrel{2x}{2\cdot 4}~~,~~\stackrel{y}{5})}\implies (8~~,~~5)
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3 years ago
PLEASE HELP!!
erik [133]
2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha

1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}

3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x
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3 years ago
Write an equivalent equation for 36x+12
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We can factor a 12 out of both terms. This leaves us with the expression 12(3x + 1), which is equivalent.
6 0
4 years ago
seven years ago beths son was one third her age at the time. seven years from now he will be one half her age. how old is beth's
elixir [45]
Easy
Anwer:
15 and 17
Step by step explanation:
34-7x=2y
-13 -13
(15,17)
I hope this helps have a good day
5 0
3 years ago
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