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aleksklad [387]
3 years ago
15

Please help me with this

Mathematics
1 answer:
postnew [5]3 years ago
3 0

Answer:

(-1, 2/3).

Step-by-step explanation:

Taking the derivative of f, we get f' = x^2 - 1 = 0.  Thus, x = -1 and x = +1.

At the relative max, y = (1/3)(-1)^3 - (-1) = -1/3 + 1 = 2/3.

The relative maximum is at (-1, 2/3).

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oksian1 [2.3K]
Idek i need points man
4 0
3 years ago
Martin sorted the bolts in his toolbox by size they measured 3/8in 1/2in 5/8in 7/8in 1 4/8in what is the difference in length be
blsea [12.9K]
The longest bolt is 1 4/8 inches, and the shortest bolt is 3/8 inch.

Subtract 3/8 from 1 4/8 to get 1 1/8 inch difference.
5 0
3 years ago
A G.P has its 3rd term and 7th term as 45 and 3645 respectively. what is the product of its 2nd and 4th
Ede4ka [16]

Answer:

2,025

Step-by-step explanation:

Given:

Third term ar² = 45

Seventh term ar⁶ = 3,645

Find:

ar x ar³

Computation:

From 7th term / 3rd term

ar⁶ / ar² = 3,645 / 45

r⁴ = 81

r = 3

So,

ar² = 45

a(3)² = 45

a = 5

So,

ar x ar³

(5)(3) x (5)(3)³

2,025

3 0
3 years ago
The heights of women aged 20 to 29 are approximately normal with mean 64 inches and standard deviation 2.7 inches. Men the same
ohaa [14]

Answer:

z=(x-mu)/o

Step-by-step explanation:

X - Heights of women aged 20 to 29: X is N(64, 2.7)

Y - Heights of men aged 20 to 29: X is N(69.3, 2.8)

a) X=6'=72"

b) Y = 72"

c) 72' women can be taken as very tall but men moderately taller than average

d) Y<5'5" =65"

e) X>73"

Z>

Almost 0% can be taken

f) IQR =Q3-Q1

3 0
3 years ago
*30 POINTS* In a group of 53 children, 22 had a dog, 18 had a cat, and 6 had both a dog and a cat. How many children had neither
Gnesinka [82]

Answer:

7

Step-by-step explanation:

Although I don’t see that answer, with 53 children and 22 having a dog, 18 a cat, and 6 with both, you would think to subtract all three of those numbers with 53 to get the remaining with no dogs or cats, which results to 7

6 0
3 years ago
Read 2 more answers
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