Answer:
√20 or 4.47 ish
Step-by-step explanation:
√(1--3)²+(-2--4)²
√(1+3)²+(-2+4)²
√(4)²+(2)²
√16+4
√20
4.47 ish
(Hopefully this is correct, have a nice day!)
Answer: the company shipped 21,696 ball bearings.
Step-by-step explanation:
Each box contains 48 balls bearings and the company shipped 452 boxes, so it is a simple multiplication 452 times 48 = 21,696
The two highlighted rows show that for the same amount of blue, Purple #1 uses <u>more</u> red than Purple #2.
This means that Purple #1 is <u>a redder</u> shade of purple than Purple #2.
Purple #2 is <u>a bluer</u> shade of purple than Purple #1.
Step-by-step explanation:
The two highlighted rows show that for the same amount of blue, Purple #1 uses <u>more</u> red than Purple #2.
- Making blue's quantity as 3 parts for purple #1 implies red part becomes 1.5 to maintain the ratio 1:2
- Purple #1 has 1/3 parts red and 2/3 parts blue. Purple #2 has 1/4th part red and 3/4th part blue.
- Hence, Purple #1 is <u>a redder</u> shade of purple than Purple #2.
- From the above explanation, Purple #2 is <u>a bluer</u> shade of purple than Purple #1.
Answer:
The margin of error needed to create a 99% confidence interval estimate of the mean of the population is of 0.3547
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
![\alpha = \frac{1-0.99}{2} = 0.005](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B1-0.99%7D%7B2%7D%20%3D%200.005)
Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so ![z = 2.575](https://tex.z-dn.net/?f=z%20%3D%202.575)
Now, find the margin of error M as such
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
In which
is the standard deviation of the population and n is the size of the sample.
In this question:
![\sigma = 1.27, n = 85](https://tex.z-dn.net/?f=%5Csigma%20%3D%201.27%2C%20n%20%3D%2085)
So
![M = z*\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=M%20%3D%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
![M = 2.575*\frac{1.27}{\sqrt{85}}](https://tex.z-dn.net/?f=M%20%3D%202.575%2A%5Cfrac%7B1.27%7D%7B%5Csqrt%7B85%7D%7D)
![M = 0.3547](https://tex.z-dn.net/?f=M%20%3D%200.3547)
The margin of error needed to create a 99% confidence interval estimate of the mean of the population is of 0.3547