If the center is (0, 0), then there is no side to side or up or down motion. The center is at the origin. The standard form of a circle is (x-h)^2 + (y-k)^2 = r^2. Your h and your k are both 0's, so just fill in and square the radius:
x^2 + y^2 = 64
Answer: To add or subtract radicals, the indices and what is inside the radical (called the radicand) must be exactly the same. If the indices and radicands are the same, then add or subtract the terms in front of each like radical. If the indices or radicands are not the same, then you can not add or subtract the radicals.
1.x^2 +6x - 4 = 6x
X^2 + 6x -4 - 6x = 0
X^2 - 4 = 0
By difference of two squares :
X^2 - 4 = 0 can be written as (x-2) (x+2) = 0
(X-2)=0 therefore x= 2
(X+2)=0 therefore x= -2
2. X^2 - 8x = -6x
X^2 -8x + 6x = 0
X^2 - 2x = 0
X(X-2) = 0
X= 0, X= 2
Answer:
1.8
Step-by-step explanation:
Solve for x
90
x
=
81
+
25
x
2
Subtract
25
x
2
from both sides of the equation.
90
x
−
25
x
2
=
81
Subtract
81
from both sides of the equation.
90
x
−
25
x
2
−
81
=
0
Factor the left side of the equation.
Tap for more steps...
−
(
5
x
−
9
)
2
=
0
Multiply each term in
−
(
5
x
−
9
)
2
=
0
by
−
1
Tap for more steps...
(
5
x
−
9
)
2
=
0
Set the
5
x
−
9
equal to
0
.
5
x
−
9
=
0
Solve for
x
.
Tap for more steps...
x
=
9
5
The result can be shown in multiple forms.
Exact Form:
x
=
9
5
Decimal Form:
x
=
1.8
Mixed Number Form:
x
=
1
4
5
Upgrade to
Answer:
There are 18 students in Grade 7, 10 are in band, so 10/18 = 0.56 are in band.
There are 12 students in Grade 8, 10 are in band, so 10/12 = 0.83 are in band.
Students in Grade 8 are more likely to be members of the band.There are 18 students in Grade 7, 10 are in band, so 10/18 = 0.56 are in band.
There are 12 students in Grade 8, 10 are in band, so 10/12 = 0.83 are in band.
Students in Grade 8 are more likely to be members of the band.
