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3 years ago

17.

2 answers:

7 0

$HEY THERE!!$

The correct answer is g is greater then equal to 5

because in an absolute value function the value must go above but if we put any rest value it will get negetive so the correct answer is (A )

HOPE IT HELPED YOU.

Ugo [173]3 years ago

4 0

The correct answer is A) g≥5

This is because when you look at an absolute value function, the constant at the end is the y value of the vertex. Since it is an absolute value equation, we know that the values can only go up. Therefore, it must be greater than or equal to the constant at the end (5)

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Estimate each quotient tell <br> which method you used

cupoosta [38]

I would do 3+5 so then it equals 8

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3 years ago

Abraham is taking his mother out to a restaurant for a mother's day dinner . He orders a meal that cost \$12 and his mom orders

White raven [17]

Answer:

$38.26

Step-by-step explanation:

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3 years ago

JESUS I DONT GET THIS SOMETIMES, PEOPLE BE LIKE "X=69420" WHEN THE PROBLEM IS IN GRAPH FORM IM SO CONFUSED LIKE IM SORRY THAT WE

puteri [66]

Answer:

Equation: y = -3x -2

Graph: Attached below ↓↓↓↓↓

Step-by-step explanation:

The equation is y = -3x + b

We need B at this point.

Since we have a point given to us,( -2, 4)we can input the x and y

Solve:

4 = -3(-2) + b

4 = 6 + b

b = -2

So the equation we have is y = -3x -2

Let's graph the line.

We go 2 units below the x-axis, because the y-intercept is -2, and the slope is -3, so we go down 3 units, and to the right 1.

Picture attached:

-Chetan K

4 0

3 years ago

Romeo will roll a 6-sided number cube, numbered 1-6, twice. What is the probability of rolling an odd number on the 1st roll and

elena-s [515]

1st rol= 3/6
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8 0

2 years ago

Suppose that det(a) = a b c d e f g h i = 2 and find the determinant of the given matrix. a b c −4d −4e −4f a + g b + h c + i

zhuklara [117]

I'll go out on a limb and suppose you're given the matrix

$\mathbf A=\begin{bmatrix}a&b&c\\d&e&f\\g&h&i\end{bmatrix}$

and you're asked to find the determinant of $\mathbf B$ , where

$\mathbf B=\begin{bmatrix}a&b&c\\-4d&-4e&-4f\\a+g&b+h&c+i\end{bmatrix}$

and given that $\det\mathbf A=2$ .

There are two properties of the determinant that come into play here:

(1) Whenever a single row/column is scaled by a constant $k$ , then the determinant of the matrix is scaled by that same constant;

(2) Adding/subtracting rows does not change the value of the determinant.

Taken together, we have that

$\det\mathbf B=-4\det\mathbf A=-8$

5 0

3 years ago