Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Answer:
x = 2
Step-by-step explanation:
You are solving for the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
PEMDAS is the order of operation, and =
Parenthesis
Exponents (& Roots)
Multiplication
Division
Addition
Subtraction.
First, subtract 25 from both sides of the equation:
5x + 25 (-25) = 35 (-25)
5x = 35 - 25
5x = 10
Isolate the variable, x. Divide 5 from both sides:
(5x)/5 = (10)/5
x = 10/5
x = 2
x = 2 is your answer.
~
Sn = n/2 (a1+an)
= 8/2 (3-38)
= 4 (-35)
= -140
4/11 is 0.363636363636
And "36" just keeps repeating
