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vladimir2022 [97]
3 years ago
7

A group of 40 bowlers showed that their average score was 192. Assume the population standard deviation is 8. Find the 95% confi

dence interval of the mean score of all bowlers.
Mathematics
1 answer:
kodGreya [7K]3 years ago
5 0

Answer:

CI=189.5,194.5

Step-by-step explanation:

From the question we are told that:

Sample size n=40

Mean \=x =192

Standard deviation\sigma=8

Significance Level \alpha=0.05

From table

Critical Value of Z=1.96

Generally the equation for momentum is mathematically given by

 CI =\=x \pm z_(a/2) \frac{\sigma}{\sqrt{n}}

 CI =192 \pm 1.96 \frac{8}{\sqrt{40}}

 CI=192 \pm 2.479

 CI=189.5,194.5

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