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tamaranim1 [39]
3 years ago
11

This graph shows a proportional relationship. What is the constant of proportionality? Enter your answer as a ratio in simplifie

d form in the box. $$ A graph with a line running through coordinates left parenthesis 0 comma 0 right parenthesis and coordinates left parenthesis 2 over 3 end fraction comma 3 over 4 end fraction right parenthesis.
plezz help fro a mager test
Mathematics
2 answers:
VladimirAG [237]3 years ago
8 0

Answer:

\frac{9}{8}

Step-by-step explanation:

The constant of proportionality is the slope, k,  of the line in the formula:

y = kx

The constant of proportioanlity can be calculated using the formula for slope:

k=\frac{y_{1}-y_{2}}{x_{1}-x_{2}}\\\\k=\frac{\frac{3}{4}-0}{\frac{2}{3}-0}\\\\k=\frac{\frac{3}{4}}{\frac{2}{3}}\\\\k=\frac{3}{4} *\frac{3}{2} \\\\k=\frac{9}{8}

AnnyKZ [126]3 years ago
4 0

The answer is 5/4. I just took the test.

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1 pts
azamat

Answer:

y=-3x+3

Step-by-step explanation:

3 0
2 years ago
Plz help me answer the whole page
dangina [55]
#2 5.88 #3 6.510 #4 7.578 #5 9.835 #6 11.910 #7 3.72
8 0
3 years ago
Pls help me I’m having a hard time
Triss [41]

1. w=2

2. x=2

3. y=-5

4. a=1

if these helped please mark brainliest

8 0
3 years ago
Write 350 as a product of primes. Use index notation when giving your answer
Mkey [24]

Answer:

5² x 7 x 2

Step-by-step explanation:

350

= 35 x 10

= 7 x 5 x 5 x 2

= 5² x 7 x 2

8 0
2 years ago
Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they
Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0
3 years ago
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