The commutative propertyof addition says, "that you will get the same answer whether you are adding 1+2 or 2+1. this also works for 2 or more number."
I hope this helps!
Answer:
Step-by-step explanation:
The equation is x^4 – 5x^2 – 36 = 0
We will break the middle term:
Firstly multiply the coefficient of x^4 by constant term of the equation:
1*36 = 36
Now find any two numbers whose product is 36 and their sum or difference is equal to 5
9*4 = 36
9-4 = 5
Now,
x^4 – 5x^2 – 36 = 0
x^4-9x^2+4x^2-36=0
Now take the common:
x^2(x^2-9)+4(x^2-9)=0
(x^2+4)(x^2-9)=0
x²+4=0,
x²= 0-4,
x²=-4,
Take root on both sides:
√x²=+/-√-4
+/-√-4 = +/-√-1 *√4
√-1 = i
Then +/-√-1 *√4 = √4 i
We know that the root of 4 is 2
Then we can write it as +/-2i
Thus x = 2i , -2i
Now (x^2-9)= 0
x²=0+9
x²=9
Take square root on both sides:
√x²=√9
x=+/-3
x= 3, -3
Therefore the values of x are 2i, -2i, 3 , -3 ....
Answer: $86.25
Step-by-step explanation:
For this problem, we are given p, r, t.
p=70 (starting amount)
r=0.11 (11%)
t=2 (years)
We can plug this into the equation B=p(1+r)^t
B=70(1+0.11)^2
B=86.247
Sam would have $86.25
Answer:
in 84 minutes or 1 hr, 24 min
Step-by-step explanation:
you need to find the least common multiple of 2, 3 and 28 which is 84
