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2 years ago

An arithmetic series is represented by the equation S24 = 2-6+058. Which of the following is true?

Mathematics

2 answers:

joja [24]2 years ago

8 0

Answer:

The answer is C

Step-by-step explanation:

took the unit test

bagirrra123 [75]2 years ago

5 0

Answer:C. The value of the series is equal to the value of the 1st or 24th numbers in the series.

Step-by-step explanation:

The given series is .

To find the first term of this series, we substitute k=1 to obtain:

To find the 24th term of the series, we put k=24 to get:

The value of the series is the sum of all the terms in the series.

We can find the value of the series using the formula:

In this case, the last term is .

Now let us analyse the options:

A. The value of the series is greater than the value of the 24th number in the series.

False: because 6 is not greater than 6.

B. The value of the series is between the values of the 1st and 24th numbers in the series.

False: because 6 is not between -5.5 and 6

C. The value of the series is equal to the value of the 1st or 24th numbers in the series.

True: In logics, an "or" statement (disjunction) is true if one of the alternatives is true. In this case the sum of the series is equal to the 24th number of the series because 6=6 is true

D. The value of the series is less than the value of the 1st number in the series.

False: because 6 is not less than -5.5

Step-by-step explanation:

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Find the distance between (-5,6)and (3,2).

skad [1K]

Answer:

$\displaystyle d = 4\sqrt{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formulas]: $\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}$
[Distance] [√Radical] (Parenthesis) Add/Subtract: $\displaystyle d = \sqrt{(8)^2+(-4)^2}$
[Distance] [√Radical] Evaluate exponents: $\displaystyle d = \sqrt{64+16}$
[Distance] [√Radical] Add: $\displaystyle d = \sqrt{80}$
[Distance] [√Radical] Simplify: $\displaystyle d = 4\sqrt{5}$

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