Answer:

Step-by-step explanation:





Answer:
(14, -2)
Step-by-step explanation:
To solve by using substitution, begin by solving for a variable in the first equation. Let's solve for x:

Now we know what <em>x</em> equals. Let's substitute this into the second equation:

We can then simplify:
Given equation
Combine y terms
Add 2
Divide by -11
So, we now know the value of y = -2.
To find the value of X, we can substitute the value of Y into one of the equations. Let's use the first one:

Substitute for y
Distribute 8
Add 16
So, we now know the value of x = 14.
Therefore, we know a solution to the system of equations is (14, -2).
Answer:
3 <_ x
Step-by-step explanation:
multiply both sides by 15
1/5 * 15 <_ x
15/5 <_ x
3 <_ x