Answer:
(2, -3) and r = 3.
Step-by-step explanation:
you can also plug this equation in desmos but I guess it's good to know how to do it also:
The equation of a circle is (x-h)^2 + (y-k)^2 = r^2
Now in order to make a perfect square on both sides, we need to do this:
First add 9 to both sides:
x^2 + 6x + 9 + y^2 -4y +4 = 9.
I purposely shifted it to show the perfect square created when you add 9 to both sides. Factor:
(x+3)^2 + y^2 - 4y + 4 = 9.
now the second bolded part is allso a perfect square. Factor:
(x+3)^2 + (y-2)^2 = 9
Based on the equation of a circle, the center must be at (2, -3) and the radius is the square root of 9 which is 3.
:)
Your answer would be, -6ap^3
Answer:
x = -1 ; y = 1
Step-by-step explanation:
x = -1
y = 1
Plug in the corresponding numbers to the corresponding variables:
y < -x + 1
(1) < -(-1) + 1
1 < 1 + 1
1 < 2 (True)
y > x
1 > -1 (True).
~
So 4's facts
we know that 4 times 2=8 and the associative property of multiplication says
a(bc)=(ab)c
so 7(8) (means 7 times 8) means 7((4)(2)) and associative say we can group them and say (7)(4)(2) so (4)((7)(2)) or 4(14) and 4 times 14=56
7 times 8=56
