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Reil [10]
3 years ago
11

WRITE Math How are a common denominator and a common multiple alike and different?

Mathematics
2 answers:
Vesnalui [34]3 years ago
8 0
That are different because that are not!!!!! the same ?
klio [65]3 years ago
3 0
Both are alike because they both call for multiples of numbers
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The first 2 terms of an ap is -2 and 3 how many terms are needed for the sum to be equal to 306 ​
Zepler [3.9K]

Answer:

306

Step-by-step explanation:

-2 + 3 = 1

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If Anthony wants to end his day at Navy Pier (10,9) will it be more efficient to go to the Chicago theater (0,3) and then Millen
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Distance formula
D = √((x1 - x2)2 + (y1 - y2)2) We have three distances that we are dealing with. Between the Theater and the Park, between the Theater and the Pier, and between the Park and the pier. In both routes we have to go between the Theater and the Park. The distance between those is the same regardless of which way we go, so we can ignore doing the math for that. That leaves us two distances. Let's plug them in. Theater to PierD = √((0 - 10)2 + (3 - 9)2) = √(100 + 36) ≈ 11.6619 Park to PierD = √((2 - 10)2 + (1 - 9)2) = √(64 + 64) ≈ 11.3137 11.3 < 11.7 
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3 years ago
The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st
Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

v=\frac{d}{t}.

Applying this to our problem we have that

v=\frac{200m}{6.509s}= 30.726m/s.

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that v=\frac{d}{t}. This formula implies that

  1. t=\frac{d}{v}.

First, observer that 19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s.

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.

Then, applying 1) we have that

t=\frac{200m}{36.003m/s}=5.5549s.

So, Sam Whittingham’s time through the 200 m was 5.5549s.

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