if you have 1.27*10^-36= [Cu2+][X2-] then you can set both those values equal to x because they're stoichimetrically equal.
1.27*10^-36=x^2
Take the square root of both sides.
1.13*10^-18=x
That would be your solubility.
Answer:
The answer to your question is the mass of solute = 53.5 g
Explanation:
Data
mass of solution = 482 g
mass of solute = ?
mass percent = 11.1 %
Mass percent is a unit of concentration. It measures the mass of the solute divided by the total mass of the solution
Process
1.- Write the formula
Mass percent = mass of solute / mass of solution x 100
-Solve for mass of solute
mass of solute = Mass percent x mass of solution / 100
2.- Substitution
mass of solute = 11.1 x 482 / 100
3.- Simplification
mass of solute = 5350.2 / 100
4.- Result
mass of solute = 53.5g
Creative Biolabs can provide various custom BsAbs in the format of Tandem scFv.
https://www.creative-biolabs.com/bsab/category/tandem-scfv-27.htm
Answer:
Evaporated via combustion.
Explanation:
The loss on ignition (LOI) and Ash content are inorganic analytical techniques used to determine the percentage by mass of hydrocarbon in compounds. This process allows volatile matter and possibly impurities found in a material to evaporate, leaving behind the true chemical constituents of the material.
The 10kg lost could be moisture content of the tree, or other volatile matter which has escaped on combustion of the tree.
Answer:
0.4762 J/g°C.
Explanation:
<em>The amount of heat released to water = Q = m.c.ΔT.</em>
where, m is the mass of water (m = 15.0 g).
c is the specific heat capacity of water = ??? J/g°C.
ΔT is the temperature difference = (final T - initial T = 37.0°C - 30.0°C = 7.0°C).
<em>∴ The specific heat capacity of water = c = Q/m.ΔT</em> = (50.0 J)/(15.0 g)(7.0°C) = <em>0.4762 J/g°C.</em>