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zzz [600]
4 years ago
15

What occurs during electrolysis? Low-energy reactants become high-energy products. High-energy reactants become low-energy produ

cts. Unreactive elements become reactive elements. Reactive elements become unreactive elements.
Chemistry
1 answer:
Nonamiya [84]4 years ago
4 0

Answer:

Low-energy reactants become high-energy products.  

Explanation:

In electrolysis, you are forcing a reaction to occur that otherwise wouldn't happen.

You are pumping energy into the system and converting low-energy reactants into high-energy products.

B is wrong. Nature tends  to run downhill energetically, so high-energy reactants tend to form low-energy products spontaneously.

C and D are wrong. If an element is unreactive, it stays unreactive, and vice versa. You can't change the nature of an element.

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PLEASE HELP ME YOU DONT HAVE TO DO WORK JUST TELL ME IF ITS RIGHT ON THE ORGANIC AND INORGANIC SIDE PLEASEE
Fittoniya [83]

Answer:

Its right you dont have to change anything

3 0
3 years ago
How many periods does the modern periodic table have?
dusya [7]
There are 7 periods in the modern periodic table

8 0
3 years ago
A 112 gram sample of an unknown metal was heated from 0.0C to 20.0C. The sample absorbed 1004 J of energy. What was the specific
worty [1.4K]

Answer:

The specific heat of the sample unknown metal is approximately 0.45 J/g °C.

General Formulas and Concepts:
<u>Thermodynamics</u>

Specific Heat Formula: \displaystyle q = mc \triangle T

  • <em>m</em> is mass (g)
  • <em>c</em> is specific heat capacity (J/g °C)
  • Δ<em>T</em> is the change in temperature

Explanation:

<u>Step 1: Define</u>

<em>Identify variables.</em>

<em>m</em> = 112 g

Δ<em>T</em> = 20.0 °C

<em>q</em> = 1004 J

<u>Step 2: Solve for </u><u><em>c</em></u>

  1. Substitute in variables [Specific Heat Formula]:                                        \displaystyle 1004 \ \text{J} = (112 \ \text{g})(c)(20.0 \ ^{\circ} \text{C})
  2. Simplify:                                                                                                        \displaystyle 1004 \ \text{J} = (2240 \ \text{g} \ ^\circ \text{C})c
  3. Isolate <em>c</em>:                                                                                                        \displaystyle c = 0.448214 \ \text{J} / \text{g} \ ^\circ \text{C}
  4. Round [Sig Figs]:                                                                                          \displaystyle c \approx 0.45 \ \text{J} / \text{g} \ ^\circ \text{C}

∴ specific heat capacity <em>c</em> is equal to around 0.45 J/g °C.

---

Topic: AP Chemistry

Unit: Thermodynamics

5 0
3 years ago
Interpretacao gerais das praticas <br>sobre densidade de amostra solido e liquido<br>​
Savatey [412]

Answer:

O sólido tem densidade mais alta em comparação ao líquido.

Explicação:

A densidade da amostra sólida é maior do que a densidade do líquido porque há pouco espaço entre as partículas do sólido. A densidade tem relação inversa com o volume de uma substância, se uma substância ocupa mais espaço então sua densidade é menor, enquanto se a substância ocupa menos espaço então tem maior densidade. As substâncias sólidas ocupam menos espaço em comparação com as substâncias líquidas, então podemos dizer que a densidade do sólido é maior do que as substâncias líquidas.

6 0
3 years ago
At a fixed volume, a four-fold increase in the temperature of a gas will lead to _______ in pressure.
timofeeve [1]

Answer:

D) a four-fold increase

Explanation:

According to Gay-Lussac's law, which states that the pressure of a given amount of gas is directly proportional to the temperature at a constant volume, the pressure increases with an increase in temperature.

According to this question, at a fixed volume, a four-fold increase in the temperature of a gas will lead to a four-fold increase in the pressure as well.

5 0
3 years ago
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