Hello,
1) p∧(q∨¬p)=(p∧q)∨(p∧¬p)=p∧q proof:
2)
p|q|¬p|q∨¬p|p∧(q∨¬p)|p∧q
0|0|..1|.......1|..............0|0
0|1|..1|.......1|..............0|0
1|0|..0|.......0|..............0|0
1|1|..0|.......1|..............1|1
All we have to do is subtract 11 - 13 to get our answer.
Answer: A) z = -2.
Hi There! The answer is 10 and 1. Because you add 10 and 1 to get 11 and 10 times 1 equals 10. Hope this helps.
Graph each point of these in the graph
6,-9
0,-6
9,9
