All categories

3 years ago

Factor completely 2x^2 − 2x − 40.

Mathematics

1 answer:

zubka84 [21]3 years ago

3 0

Step-by-step explanation:

Hey there!

Given;

$= 2 {x}^{2} - 2x - 40$

Solve it by using mid-term factorization.

$= 2 {x}^{2} - 2x - 40$

$= 2 {x}^{2} - (10 - 8)x - 40$

$= 2 {x}^{2} - 10x + 8x - 40$

Take common and simplify them to get answer.

$2x(x - 5) + 8(x - 5)$

$= (2x + 8)(x - 5)$

$= 2(x + 4)(x - 5)$

Therefore the answer is option D.

Hope it helps..

You might be interested in

Does the graph represent a function?

makkiz [27]

Step-by-step explanation:

answer no plsssssssssssssssssssssssssssse mark as brainliest

8 0

2 years ago

Can anyone help me with this? Reduce the fraction

Elden [556K]

$\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \cfrac{-20t^5u^2v^3}{48t^7u^4v}\implies \cfrac{-20}{48}\cdot \cfrac{t^5u^2v^3}{t^7u^4v^1}\implies \cfrac{-5}{12}\cdot \cfrac{v^3v^{-1}}{t^7t^{-5}u^4u^{-2}}\implies \cfrac{-5}{12}\cdot \cfrac{v^{3-1}}{t^{7-5}u^{4-2}} \\\\\\ \cfrac{-5}{12}\cdot \cfrac{v^2}{t^2u^2}\implies \cfrac{-5v^2}{12t^2 u^2}$

3 0

3 years ago

Which step was the first error made? -3\left(2x-3\right)=33−3(2x−3)=33 -6x+6=33−6x+6=33 step 1 -6x=27−6x=27 step 2 \frac{\left(-

Afina-wow [57]

Given:

The equation is

$-3(2x-3)=33$

The incorrect solution steps are given.

To find:

The first error.

Solution:

We have,

$-3(2x-3)=33$

Using distributive property, we get

$-3(2x)-3(-3)=33$

$-6x+9=33$

The given step 1 is $-6x+6=33$ , which is not correct.

Therefore, there is first error in step 1 because the distribution property is not used properly.

Hence, the correct option is D.

6 0

3 years ago

how to find the area of each circle. use a calculator value of pi. round the answer to the nearest tenth

tankabanditka [31]

Answer:

A = 201.0 mi^2

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

We know that r = 8

A = (3.14) *8^2

A = 3.14 * 64

A = 200.96 mi ^2

Rounding to the nearest tenth

A = 201.0 mi^2

8 0

3 years ago

Read 2 more answers

(-4x^2+3xy-y^2)/-(-7x^2-xy+6y^2)/(x^2+4xy-2y^2)

Brut [27]

Alright, so we can start off by dividing
-4x^2+3xy-y^2 by -(-7x^2-xy+6y^2)=7x^2+xy-6y^2 using long division, getting

-4/7
 _____________________
7x^2+xy-6y^2 -4x^2+3xy-y^2
- (-4x^2-4xy/7-24y^2/7)
__________________
25xy/7+31y^2/7

Since we can't do anything at this point, we do
-4/7+(25xy/7+31y^2/7)/(7x^2+xy-6y^2)

At this point, we can divide this by
(x^2+4xy-2y^2), resulting in
(-4/7+((25xy/7+31y^2/7)/(7x^2+xy-6y^2)))/((x^2+4xy-2y^2)). After that, we can't use long division since the numerator's top x exponent is 1.

6 0

3 years ago