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3 years ago

In a survey 9 out of 15 named math as their favorite class. express this rate as a decimal

Mathematics

1 answer:

ZanzabumX [31]3 years ago

3 0

0.6 is 9/15 as a decimal.

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The points with coordinates (x, -1), (2,2), and (4,3) lie on the same line. What is the value of x?

borishaifa [10]

Find the slope of the line passing throught the points (2, 2) and (4, 3).

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Substitute:

$m=\dfrac{3-2}{4-2}=\dfrac{1}{2}$

If the point (x, -1) lie on the same line, then the slope of line passing through the points (2, 2) and (x, -1) the same:

Substitute:

$m=\dfrac{-1-2}{x-2}=\dfrac{-3}{x-2}$

We have the equation:

$\dfrac{-3}{x-2}=\dfrac{1}{2}$ <em>cross multiply</em>

$(1)(x-2)=(-3)(2)$

$x-2=-6$ <em>add 2 to both sides</em>

$x=-4$

<h3>Answer: x = -4.</h3>

7 0

3 years ago

Solve the inequality for x. 75+15x is greater than or equal to 140

Gre4nikov [31]

75+ 15x ≥ 140
⇒ 15x ≥ 140 -75
⇒ 15x ≥ 65
⇒ x ≥ 65/15
⇒ x ≥ 13/3
⇒ x ≥ 4 1/3

The final answer is x ≥ 4 1/3~

8 0

3 years ago

PLEASE HELP QUICK I AM IN A RUSH

Alekssandra [29.7K]

C because it simplifies to 0=0 which proves that it has infinite solutions!

7 0

3 years ago

Read 2 more answers

Which expression is modeled by this se of arrows in the number line

Bond [772]

Answer:

Step-by-step explanation:

7 0

3 years ago

The pipe fitting industry had 546.5 thousand jobs in 2015 and is expected to decline at an average rate of 3 thousand jobs per y

lesya692 [45]

Answer:

The amount of jobs from fitting industry shall decline in 5.5 percent from 2015 to 2025.

Step-by-step explanation:

Due to the assumption of a yearly average rate, a linear function model shall be used. The expected amount of jobs ( $n$ ) after a certain amount of years (t) is given by the following formula:

$n = n_{o} + \frac{\Delta n}{\Delta t}\cdot t$

Where:

$n_{o}$ - Initial amount of jobs in pipe fitting industry, measured in thousands.

$\frac{\Delta n}{\Delta t}$ - Average yearly rate, measured in thousands per year. (A decline is indicated by a negative sign)

If $n_{o} = 546.5$ , $t = 2025-2015 = 10\,years$ and $\frac{\Delta n}{\Delta t} = -3\,\frac{1}{years}$ , then:

$n = 546.5+\left(-3\,\frac{1}{year}\right)\cdot (10\,years)$

$n = 516.5$

The percent change in jobs from pipe fitting industry is calculated as follows:

$\%n = \left(1-\frac{n}{n_{o}}\right)\times 100\,\%$

$\% n = \left(1-\frac{516.5}{546.5}\right)\times 100\,\%$

$\%n = 5.5\,\%$

The amount of jobs from fitting industry shall decline in 5.5 percent from 2015 to 2025.

4 0

3 years ago