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Masja [62]
3 years ago
13

If someone can please answer the question in the picture thatd be great

Mathematics
1 answer:
Ann [662]3 years ago
5 0

Answer:

≈ 20.8 ft

Step-by-step explanation:

A right triangle is formed between the wall, the ground and the ladder.

The ladder is the hypotenuse , the wall and ground are the legs.

let h be the height of the wall, then using Pythagoras' identity

h² + 33² = 39²

h² + 1089 = 1521 ( subtract 1089 from both sides )

h² = 432 ( take the square root of both sides )

h = \sqrt{432} ≈ 20.8 ft ( to the nearest tenth )

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The standard eq'n of a circle is (x-h)^2 + (y-k)^2 = r^2

Let's subst. what we know:  we get   (x-3)^2 + (y-1/2)^2 = (9/2)^2.  Note that y = 1/2 is halfway between y=-4 and y=5.</span>
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What is pie in decimals
liubo4ka [24]
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Convert 39 meters squared to yard square
horrorfan [7]

Answer:

I used this converter, very helpful

Step-by-step explanation:


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3 years ago
Martin wants to use coordinate geometry to prove that the opposite sides of
romanna [79]

The correct answer is option A which is the distance between A and D will be  AD = \sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b.

<h3>What is coordinate geometry?</h3>

A coordinate plane is a 2D plane which is formed by the intersection of two perpendicular lines known as the x-axis and y-axis.

The formula utilised to find the distance between two points is;-

X = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2

We have the coordinates of the point A = (0, 0) and D is  (0, b).By applying the formula to find the distance between A and D.

AD = \sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b.

Therefore the correct answer is option A which is the distance between A and D will be  AD = \sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b.

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4 0
2 years ago
A spring has natural length 20 cm. Compare the work W1 done in stretching the spring from 20 cm to 30 cm with the work W2 done i
sashaice [31]

Answer:

W1 = W2 = 50k Joules (assuming W1 and W2 have the same force constant, k)

W1 - W2 = 0

Step-by-step explanation:

Work done in stretching a spring is given by 1/2ke^2

Where, k is force constant and e is extension

e1 = 30cm - 20cm = 10cm

W1 = 1/2k(e1)^2 = 1/2×k×10^2 = 50k Joules

e2 = 40cm - 30cm = 10cm

W2 = 1/2k(e2)^2 = 1/2×k×10^2 = 50k Joules

W1 = W2 = 50k Joules provided W1 and W2 have equal force constant

Therefore, W1 - W2 = 0

7 0
3 years ago
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