I need to calculate the degree of x=tan^-1(21.3/23)
1 answer:
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Answer: C, A, D
edit - sorry the title was wrong earlier
Step-by-step explanation:
Question 1
in the quadratic formula, the equation is in the format of ax^2 + bx + c
so rearrange this equation so all values are on one side
-6x^2 = -9x + 7
-6x^2 + 9x - 7 =0
so a = -6, b = 9, c = -7
answer = C
Question 2
note that all the values are already on one side for this, so repeat the process from question 1 where the equation is in the format of ax^2 + bx + c
the equation = −6x2 − 8x + 12 = 0
so a = -6, b = -8, c = 12
answer = A
Question 3
(see picture below for steps)
following the same process above, a = 4, b = 45, and c = 24, so plug these values in the quadratic equation shown in the picture below
so you get the answers x = -10.69 and x = -0.56 after putting them in a calculator
answer = D
