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umka21 [38]
3 years ago
12

In radian measure, the angles of a 45-45-90 triangle are:

Mathematics
2 answers:
jeka943 years ago
8 0

Answer:

The answer is the option A \frac{\pi}{4},\frac{\pi}{4},\frac{\pi}{2}

Step-by-step explanation:

we know that

The measure of \pi radians is equal to 180\°

so by proportion

Find the measure in radians of  45\°

\frac{\pi}{180}\frac{radians}{degrees}=\frac{x}{45}\frac{radians}{degrees}\\ \\x=(45/180)*\pi \\ \\x=\frac{\pi}{4}

Find the measure in radians of  90\°

\frac{\pi}{180}\frac{radians}{degrees}=\frac{x}{90}\frac{radians}{degrees}\\ \\x=(90/180)*\pi \\ \\x=\frac{\pi}{2}

therefore

In radian measure the angles are

\frac{\pi}{4},\frac{\pi}{4},\frac{\pi}{2}

Phoenix [80]3 years ago
3 0
Pie/4 , pie/4 , pie/2
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Answer:

y - Q =  -  \frac{1}{4}(x - P)

Step-by-step explanation:

Line g passes through (-2,6) and (-3,2).

The slope of line g is given by:

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Let's substitute the values to get:

\frac{2 - 6}{ - 3 -  - 2}= \frac{ - 4}{ - 1}  = 4

The equation that is perpendicular to line g will have a slope that is the negative reciprocal of 4.

i.e -1/4

If this line passes through (P,Q), then the equation is:

y - Q =  - \frac{1}{4} (x - P)

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3 years ago
What is the completely factored form of d4 -8d2 + 16
irinina [24]
According to Vieta's Formulas, if x_1,x_2 are solutions of a given quadratic equation:

ax^2+bx+c=0

Then:

a(x-x_1)(x-x_2) is the completely factored form of ax^2+bx+c.

If choose x=d^2, then:

\displaystyle x^2-8x+16=0\\\\x_{1,2}= \frac{8\pm  \sqrt{64-64} }{2}=4

So, according to Vieta's formula, we can get:

x^2-8x+16=(x-4)(x-4)= (x-4)^2

But x=d^2:

d^4-8d^2+16=(d^2-4)^2=[(d+2)(d-2)]^2=(d+2)^2(d-2)^2
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3 years ago
What is the center and radius of a circle whose equation is x2 + y2 -2x -6y -5 = 0?
ddd [48]

x²+y²-2x-6y-5=0

x²-2x+y²-6y=5

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2 years ago
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7 0
4 years ago
What is the exact value of cos (67.5° )?
Brilliant_brown [7]

Answer:

0.38268343

Step-by-step explanation:

cos( 67.5 )

Rewrite  

67.5

as an angle where the values of the six trigonometric functions are known divided by  2 . cos ( 135\ 2)

Apply the cosine half-angle identity.

±

√

1

+

cos

(

135

)

2

 

Change the  

±

to  

+

because cosine is positive in the first quadrant.

√

1

+

cos

(

135

)

2

Simplify  

√

1

+

cos

(

135

)

2

√

2

−

√

2

2

The result can be shown in multiple forms.

Exact Form:

√

2

−

√

2

2

Decimal Form:

0.38268343

…

6 0
4 years ago
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