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Musya8 [376]
3 years ago
8

3.3 x 10*9 +2.6 x 10*9 +7.7 × 10*8 ​

Mathematics
2 answers:
Ostrovityanka [42]3 years ago
8 0

Answer:

1147 okayyyyyyyyyyyyyyyyyyhhhhyhhhhhhyyyyyyyy

ivolga24 [154]3 years ago
7 0

Answer:

23.4x10+913

Step-by-step explanation:

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What is the sound level for a noise that has an intensity of 9.9 × 10-5 watts/m2?
lisabon 2012 [21]

we can use

sound level formula

\beta=10log(\frac{I}{I_0} )dB

where

\beta is the sound level for a noise

I is intensity given

I0 is reference intensity

we know that reference intensity as

I_0=1*10^{-12}W/m^2

we are given

I=9.9*10^{-5}W/m^2

now, we can plug these values

and we get

\beta=10log(\frac{9.9*10^{-5}W/m^2}{1*10^{-12}W/m^2} )dB

now, we can simplify it

\beta=10log(9.9*10^{-5+12} )dB

\beta=79.95635dB................Answer


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