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Leno4ka [110]
3 years ago
6

Identify the "inside function" u = f(x) and the "outside function" y = g(u). Then find dy/dx using the Chain Rule.

Mathematics
1 answer:
skad [1K]3 years ago
5 0
DfLet f(x)=\sec x and g(x)=\sqrt x. Then

y=\sec\sqrt x=\sec(g(x))=f(g(x))=f\circ g(x)

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}

where u=g(x)=\sqrt x, so that y=f(g(x))=f(u)=\sec u. We have

\dfrac{\mathrm du}{\mathrm dx}=\dfrac1{2\sqrt x}
\dfrac{\mathrm d\sec u}{\mathrm du}=\sec u\tan u

and so

\dfrac{\mathrm dy}{\mathrm dx}=\sec u\tan u\dfrac{\mathrm dy}{\mathrm du}=\dfrac{\sec\sqrt x\,\tan\sqrt x}{2\sqrt x}
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