Answer:
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Explanation:
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Answer:
2.glucose move into chamber B faster than fructose
Explanation:
- Facilitated diffusion: refers to the transport of hydrophilic molecules that are not able to freely cross the membrane. Channel protein and many carrier proteins are in charge of this <u>passive transport</u>. If uncharged molecules need to be carried <u>this process depends on concentration gradients</u> and molecules are transported from a higher concentration side to a lower concentration side. If ions need to be transported this process depends on an electrochemical gradient. The glucose is an example of a hydrophilic protein that gets into the cell by facilitated diffusion. Facilitated diffusion is a passive transport process because the cell does not need any energy to make it happen.
The exposed scenario is an example of facilitated diffusion, a process that occurs in favor of the concentration gradient, and which rate depends on the concentration of molecules in each side of the membrane, in this case, glucose and fructose, among other factors that might also influence the diffusion rate. So, as the concentration of glucose is higher in chamber A (80%), and lower in chamber B (20%), in comparison with fructose, the first one will diffuse faster than fructose. The difference in concentration between both chambers is sharper in glucose, so its transport is faster than the fructose transport, which will also diffuse but at a lower rate.
Answer:
Explanation:
Molecular biology has enabled the identification of the mechanisms whereby inactive myostatin increases skeletal muscle growth in double-muscled (DM) animals. Myostatin is a secreted growth differentiation factor belonging to the transforming growth factor-β superfamily. Mutations make the myostatin gene inactive, resulting in muscle hypertrophy. The relationship between the different characteristics of DM cattle are defined with possible consequences for livestock husbandry. The extremely high carcass yield of DM animals coincides with a reduction in the size of most vital organs. As a consequence, DM animals may be more susceptible to respiratory disease, urolithiasis, lameness, nutritional stress, heat stress and dystocia, resulting in a lower robustness. Their feed intake capacity is reduced, necessitating a diet with a greater nutrient density. The modified myofiber type is responsible for a lower capillary density, and it induces a more glycolytic metabolism. There are associated changes for the living animal and post-mortem metabolism alterations, requiring appropriate slaughter conditions to maintain a high meat quality. Intramuscular fat content is low, and it is characterized by more unsaturated fatty acids, providing healthier meat for the consumer. It may not always be easy to find a balance between the different disciplines underlying the livestock husbandry of DM animals to realize a good performance and health and meat quality.
Answer:
The correct answer is - P = 0.45
Explanation:
The Chi-square test is a test that determines the assorted genes independently. Here p-values used to make conclusions in significance testing.
If the p value is less than the significance level we expect or choose, then this null hypothesis is rejected in favor of the alternative hypothesis. It p value is greater than or equal to the significance level, then we fail to reject the null hypothesis.
So in this case, as the recombination rate is 49% so the p value which satisfies the conclusion will be around 0.45 and values near to it.
When seeds germinate, a sprout begins to grow out from the seed. This is how the process of plant growth begins.
