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Inga [223]
3 years ago
14

Rachel and David were shopping for holiday gifts when they noticed a Thanksgiving sweater on the discount rack. Rachel really wa

nted the sweater, even though she wouldn’t be wearing it until Thanksgiving of 2021! Part A: ​If the original price of the sweater was $24.00, and the sweater is on sale for 60% off, what is the sale price?
Mathematics
1 answer:
Leona [35]3 years ago
8 0

Answer:

Sales\ Price = \$9.60

Step-by-step explanation:

Given

Price = \$24.00

Discount = 60\%

Required

Determine the sales price

First, we calculate the discount price

Discount\ Price = Price * Discount

Discount\ Price = \$24.00 * 60\%

Discount\ Price = \$14.4

The sales price is then calculated by subtracting the discount price from the original price of the item

Sales\ Price = Price - Discount\ Price

Sales\ Price = \$24.00 - \$14.40

Sales\ Price = \$9.60

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Using long division to find the quotient, what changes do you first
lora16 [44]

Answer:

\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4

Step-by-step explanation:

Given

Dividend = 125x^3 - 8

Divisor = 5x - 2

Required

Determine the quotient

See attachment for complete process.

First, divide 125x^3 by 5x

\frac{125x^3}{5x} =25x^2

Write 25x^2 at the top

Multiply 5x - 2 by 25x^2

= 125x^3 - 50x^2

Subtract from 125x^3 - 8

i.e.

125x^3 - 8 - (125x^3 - 50x^2) = 50x^2 - 8

Step 2:

Divide 50x^2 by 5x

\frac{50x^2}{5x} = 10x

Write 10x at the top

Multiply 5x - 2 by 10x

= 50x^2 - 20x

Subtract from 50x^2 - 8

i.e.

50x^2 - 8 - (50x^2 - 20x) = 20x - 8

Step 3:

Divide 20x by 5x

\frac{20x}{5x} = 4

Write 4 at the top

Multiply 5x - 2 by 4

= 20x - 8

Subtract from 20x - 8

i.e.

20x - 8 - (20x - 8) = 0

Hence:

\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4

8 0
3 years ago
**PLS HELP**
nadezda [96]

Answer:

I think d equation most. closely represents

4 0
3 years ago
William is saving up to buy a new phone. He already has $23 and can save
Ipatiy [6.2K]

Step-by-step explanation:

current Amount of money 23

8x10=80

80+23=103

William will have 103$ after 10 weeks

4 0
3 years ago
Which numbers are irrational?
irakobra [83]

Answer:

√14 and √42. hope this helps.

5 0
3 years ago
For what values of k the relation R:{(k2 , 5), (3k, 6)} is not a function?
Nastasia [14]

Answer:

k=0 and k=3.

Step-by-step explanation:

To this relation be a function, the horizontal coordinates can't be equal. So, let's find the value of k that makes those coordinates equal.

k^{2}=3k\\ k^{2}-3k=0\\k(k-3)=0\\

Using the null factor property, we have

k=0\\k-3=0 \implies k=3

Therefore, the given relation is not a function when k=0 and k=3.

7 0
3 years ago
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