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topjm [15]
3 years ago
9

On a coordinate plane, a parabola opens down. It goes through (negative 2, negative 2), has a vertex at (1.5, 10), and goes thro

ugh (5, negative 2).
Over which interval is the graph of f(x) = –x2 + 3x + 8 increasing?

(–∞, 1.5)
(–∞, 10.25)
(1.5, ∞)
(10.25, ∞)
Mathematics
2 answers:
romanna [79]3 years ago
6 0

Answer:

(-∞,1.5)

Step-by-step explanation:

Got it right on edge2k21

Cloud [144]3 years ago
5 0

Answer:

Step-by-step explanation:

(-∞,1.5)

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Ivan purchased stock in a company at an initial price of $8 per share. The share value reached $18 after 10 days and then began
Butoxors [25]

The quadratic equation that best represents his model of the relationship between stock value and time is given by:

y = -0.0976(x - 10)^2 + 18, x \geq 0

The graph is given at the end of the answer.

<h3>What is the equation of a parabola given it’s vertex?</h3>

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)^2 + k

In which a is the leading coefficient.

In this problem, the maximum value was a share value of $18 after 10 days, hence the vertex is:

(h,k) = (10,18).

Thus:

y = a(x - 10)^2 + 18

Since the initial price was of $8 per share, we have that:

8 = a(0 - 10)^2 + 18

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a = -\frac{8}{82}

a = -0.0976

Hence the equation is:

y = -0.0976(x - 10)^2 + 18, x \geq 0

At the end of the answer, the sketch of the graph is given.

More can be learned about quadratic equations at brainly.com/question/24737967

6 0
3 years ago
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