Since the child ticket is y-4.75 (saying y is the adult ticket), we need to solve for y in y-4.75=x. Adding 4.75 to both sides, we get y=x+4.75
Answer: ($4125)(1+0.079/12)^5(1+0.257/12)^7
Step-by-step explanation: I was in a p e x , and this question didn't have a answer so i had to guess and i did, and i was correct, and have supplied you guys with the answer
First, we determine the area of the rectangular house by multiplying the length by the width. That is,
area of the house = (50 ft)(24 ft) = 1200 ft²
Given that all sides of the house should have the pathway, the length of the house plus the pathway should be 50+2x and the new width would be 24+2x. The new area minus the original area of the house should not be more than 345 ft². Thus, the equation would be,
(50+2x)(24+2x) - 1200 ≤ 345
Area of small circle = PI x r^2
r = 1/2 the diameter ( 1/2 * 3 = 1.5)
3.14 x 1.5^2 = 7.065 square cm
there are 2 small circles so total area for them = 7.065 * 2 = 14.13 square cm
the area for the large circle = PI x r^2
the radius of the large circle is 3 cm
3.14 x 3^2 = 28.26 square cm
the area of the shaded area is: 28.26 - 14.13 = 14.13 square cm, which can round down to 14 square cm.
Suppose that one of sides is x :
Area = x²
thus :
_____________________________________________
Perimeter = 4x