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Nataliya [291]
2 years ago
7

Determine whether AB is a median,altitude,or neither

Mathematics
1 answer:
nasty-shy [4]2 years ago
7 0

Answer:

median

Step by step:

the line segment from a vertex to the midpoint of the opposite side. It is also an angle bisector when the vertex is an angle in an equilateral triangle or the non-congruent angle of an isoceles triangle.

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what's the surface area of this square pyramid that has a base length of 5 inches and triangular faces that are 9 inches tall
Vadim26 [7]

The surface area of the square prism is 115 square inches

<h3>surface area of a pyramid</h3>

The surface area of a pyramid is equivalent to the sum of the faces of the pyramid

For the given square pyramid;

TSA = (5*5) + 4(1/2 * 9 * 5)

Simplify to have;

Surface area =25 + 4(45/2)

Surface area = 25 + 180/2

Surface area = 25. + 90

Surface area = 115 square inches

Hence the surface area of the square prism is 115 square inches

Learn more on surface area here: brainly.com/question/20771646

#SPJ1

7 0
1 year ago
I was wondering what to pick for my next subjects i just did math and science
34kurt

Answer:

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8 0
3 years ago
Read 2 more answers
20 POINTS!!!!!<br> look at photo to answer!
kotykmax [81]
The very bottom all the way to the right
7 0
2 years ago
Find (tan Q)<br> the answers are in the pictures, the last answer is D.) cannot be determined
Readme [11.4K]
Q=45°
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3 0
2 years ago
What are the x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of
Mrrafil [7]

Answer:

\left ( \frac{3x_2+5x_1}{8},\frac{3y_2+5y_1}{8} \right )

Step-by-step explanation:

Given: P is Three-fifths the length of the line segment from K to J

To find: x- and y-coordinates of point P on the directed line segment from K to J

Solution:

Section formula:

Let point K and J be (x_1,y_1)\,,\,(x_2,y_2) such that the point p(x,y) divides KJ in ratio m:n

Then coordinates of point  P are given by \left ( \frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n} \right )

Take m:n=3:5

So,

coordinates of point P = \left ( \frac{3x_2+5x_1}{3+5},\frac{3y_2+5y_1}{3+5} \right )=\left ( \frac{3x_2+5x_1}{8},\frac{3y_2+5y_1}{8} \right )

7 0
3 years ago
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