I think it is the model ET-2. Not quite sure.
Answer:
public static double areaSum(Circle c1, Circle c2){
double c1Radius = c1.getRadius();
double c2Radius = c2.getRadius();
return Math.PI * (Math.pow(c1Radius, 2) + Math.pow(c2Radius, 2));
public static void main(String[] args){
Circle c1 = new Circle(6.0);
Circle c2 = new Circle(8.0);
areaSum(c1,c2);
}
Explanation:
The options listed are not related to the question. and if they were related in any sense then I would say the cheapest thing on the list is a phone card so I guess you can buy that and save the most for your travel as you can use phone cards anywhere as they have 1800 numbers which are free from any public phone.
Answer:
1. a modem connects a computer to the internet
4. a modem transmits digital signals over a telephone line
5. a dial-up modem communicates using a telephonic call
All of three mentioned above.
Modem stands for modulator de-modulator, and it connects the computer to the internet. Its not the fastest, which is router. And the connection is established via the telephone line, through which the digital signals is being transmitted, And the type used is dial up communication.
Explanation:
The answer is self explanatory.
Answer:
Check the explanation
Explanation:
#define _MULTI_THREADED
#include <pthread.h>
#include <stdio.h>
#include <errno.h>
#define THREADS 2
int i=1,j,k,l;
int argcG;
char *argvG[1000];
void *threadfunc(void *parm)
{
int *num;
num=(int*)parm;
while(1)
{
if(i>=argcG)
break;
if(*num ==1)
if(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u')
{
printf("%s\n",argvG[i]);
i++;
continue;
}
if(*num ==2)
if(!(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u'))
{
printf("%s\n",argvG[i]);
i++;
continue;
}
sched_yield();
}
return NULL;
}
int main(int argc, char *argv[])
{
pthread_t threadid[THREADS];
int rc=0;
int loop=0;
int arr[2]={1,2};
argcG=argc;
for(rc=0;rc<argc;rc++)
argvG[rc]=argv[rc];
printf("Creating %d threads\n", THREADS);
for (loop=0; loop<THREADS; ++loop) {
rc =pthread_create(&threadid[loop], NULL, threadfunc,&arr[loop]);
}
for (loop=0; loop<THREADS; ++loop) {
rc = pthread_join(threadid[loop], NULL);
}
printf("Main completed\n");
return 0;
}
The below attached image is a sample output