In client server network, there is no central server //// true or false

The program keeps track of the size of the board in cards.size(). The sub class sets this by passing it into the constructor. After that, the subclass never cares about the size of the board, so it's not necessary to make it accessible with an abstract method. Any need for it is covered by cardIndexes method.

Explanation:

The differences between Elevens and Thirteens

The program keeps track of the size of the board in cards.size(). The sub class sets this by passing it into the constructor. After that, the subclass never cares about the size of the board, so it's not necessary to make it accessible with an abstract method. Any need for it is covered by cardIndexes method.

5 0

3 years ago

Add three methods to the Student class that compare twoStudent objects. One method (__eq__) should test for equality. A second m

shusha [124]

Answer:

class Student(object):

def __init__(self, name, number):

self.name = name

self.scores = []

for count in range(number):

self.scores.append(0)

def getName(self):

return self.name

def setScore(self, i, score):

self.scores[i - 1] = score

def getScore(self, i):

return self.scores[i - 1]

def getAverage(self):

return sum(self.scores) / len(self._scores)

def getHighScore(self):

return max(self.scores)

def __eq__(self,student):

return self.name == student.name

def __ge__(self,student):

return self.name == student.name or self.name>student.name

def __lt__(self,student):

return self.name<student.name

def __str__(self):

return "Name: " + self.name + "\nScores: " + \

" ".join(map(str, self.scores))

def main():

student = Student("Ken", 5)

print(student)

for i in range(1, 6):

student.setScore(i, 100)

print(student)

print("\nSecond student")

student2 = Student("Ken", 5)

print(student2)

print("\nThird student")

student3 = Student("Amit", 5)

print(student3)

print("\nChecking equal student1 and student 2")

print(student.__eq__(student2))

print("\nChecking equal student1 and student 3")

print(student.__eq__(student3))

print("\nChecking greater than equal student1 and student 3")

print(student.__ge__(student3))

print("\nChecking less than student1 and student 3")

print(student.__lt__(student3))

if __name__ == "__main__":

5 0

3 years ago

Please add thenodes given below to construct the AVL tree show all the necessarysteps,

Paha777 [63]

Answer:

30,33,37,18,23,34,15,38,40,17

To construct the AVL tree, follow these steps and diagrams are shown in the image:

• Add 30 to the tree as the root node. Then add 33 as the right child because of 33 is greater than 30 and AVL tree is a binary search tree.

• Then add 37 as the right child of 33. Here the balance factor of node 30 becomes 0-2 = -2, unbalanced.

Use RR rotation, make node 33 the root node, 30 as the left child of 33 and 37 as the right child of 33.

• Now add 18 as the left child of 30. And 23 as the right child of 18. Here the balance factor of 30 becomes 2-0 = 2. It’s unbalanced.

Use LR rotation, make 23 the parent of 18 and 30.

• Now add 34 as the left child of 37 and 15 as the left child of 18. Add 38 as the right child of 37. And then add 40 as the right child of 38.

• Now adding 17 as the right child of 15 makes the tree unbalanced at 18.

Use LR rotation, make 17 as the parent of 15 and 18.

Explanation:

The balance factor of a node can be either 0,1 or -1. Else the tree is called unbalanced at the node.

If the inserted node is in the left subtree of the left subtree of the unbalance node, then perform LL rotation.

If the inserted node is in the right subtree of the right subtree of the unbalance node, then perform RR rotation.

If the inserted node is in the left subtree of the right subtree of the unbalance node, then perform RL rotation.

If the inserted node is in the right subtree of the left subtree of the unbalance node, then perform LR rotation.

7 0

3 years ago

In client server network, there is no central server //// true or false​

In client server network, there is no central server //// true or false