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2 years ago

What is the measure of

Mathematics

1 answer:

seraphim [82]2 years ago

7 0

Answer:

60⁰ is the answer. akksjdjd

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a small airplane flies 625 miles with an average speed of 250 mph.. 1.25 hours after the plane leaves a boeing 747 leaves from t

kipiarov [429]

Time for first plane = 625 / 250
= 2.5 hours
after 1.25 hours
boeing 747 takes 1.25 hours (2.5 - 1.25) to arrive at the same location at the same time
so, speed = distance / time
= 625 / 1.25
= 500
the average speed of the boeing 747 is 500 mph

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3 years ago

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slamgirl [31]

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3 years ago

What divided by 72 equals -13

Ivahew [28]

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3 years ago

A company sells crushed rock in 16 pound bags.each bags contains a mixture of quartz and marble

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2 years ago

Find the first six partial sums S1, S2, S3, S4, S5, S6 of the sequence whose nth term is given. 1 2 , 1 22 , 1 23 , 1 24 , . .

agasfer [191]

Answer:

the first partial sum $\mathbf{S_1= \dfrac{1}{2}}$

the second partial sum $\mathbf{S_2= \dfrac{3}{4} }$

the third partial sum $\mathbf{S_3= \dfrac{7}{8}}$

the fourth partial sum $\mathbf{S_4= \dfrac{15}{16}}$

the fifth partial sum $\mathbf{S_5= \dfrac{31}{32}}$

the sixth partial sum $\mathbf{S_6= \dfrac{63}{64}}$

Step-by-step explanation:

The term of the sequence are given as : $\dfrac{1}{2}$ , $\dfrac{1}{2^2}$ , $\dfrac{1}{2^3}$ , $\dfrac{1}{2^4 }$ , . . .

The nth term for this sequence is , $\mathtt{a_n =( \dfrac{1}{2})^n}$

The nth partial sum of the sequence for $\mathtt{a_1,a_2,a_3.... a_n}$ is $\mathtt{S_n}$

where;

$\mathtt{S_n = a_1 +a_2+a_3+ ...+a_n}$

The first partial sum is: $\mathtt{S_1= a_1}$

$\mathtt{S_1= (\dfrac{1}{2})^1}$

$\mathbf{S_1= \dfrac{1}{2}}$

Therefore, the first partial sum $\mathbf{S_1= \dfrac{1}{2}}$

The second partial sum is: $\mathtt{S_2= a_1+a_2}$

$\mathtt{S_2= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2}$

$\mathtt{S_2= \dfrac{1}{2} + \dfrac{1}{4}}$

$\mathtt{S_2= \dfrac{2+1}{4} }$

$\mathbf{S_2= \dfrac{3}{4} }$

Therefore, the second partial sum $\mathbf{S_2= \dfrac{3}{4} }$

The third partial sum is : $\mathtt{S_3= a_1+a_2+a_3}$

$\mathtt{S_3= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2+(\dfrac{1}{2})^3 }$

$\mathtt{S_3= \dfrac{1}{2} + \dfrac{1}{4}+\dfrac{1}{8}}$

$\mathtt{S_3= \dfrac{4+2+1}{8}}$

$\mathbf{S_3= \dfrac{7}{8}}$

Therefore, the third partial sum $\mathbf{S_3= \dfrac{7}{8}}$

The fourth partial sum : $\mathtt{S_4= a_1+a_2+a_3+a_4}$

$\mathtt{S_4= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2+(\dfrac{1}{2})^3+(\dfrac{1}{2})^4 }$

$\mathtt{S_4= \dfrac{1}{2} + \dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}}$

$\mathtt{S_4= \dfrac{8+4+2+1}{16}}$

$\mathbf{S_4= \dfrac{15}{16}}$

Therefore, the fourth partial sum $\mathbf{S_4= \dfrac{15}{16}}$

The fifth partial sum : $\mathtt{S_5= a_1+a_2+a_3+a_4+a_5}$

$\mathtt{S_5= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2+(\dfrac{1}{2})^3+(\dfrac{1}{2})^4 +(\dfrac{1}{2})^5 }$

$\mathtt{S_5= \dfrac{1}{2} + \dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}}$

$\mathtt{S_5= \dfrac{16+8+4+2+1}{32}}$

$\mathbf{S_5= \dfrac{31}{32}}$

Therefore, the fifth partial sum $\mathbf{S_5= \dfrac{31}{32}}$

The sixth partial sum: $\mathtt{S_5= a_1+a_2+a_3+a_4+a_5+a_6}$

$\mathtt{S_6= (\dfrac{1}{2})^1 + (\dfrac{1}{2})^2+(\dfrac{1}{2})^3+(\dfrac{1}{2})^4 +(\dfrac{1}{2})^5 +(\dfrac{1}{2})^6 }$

$\mathtt{S_6= \dfrac{1}{2} + \dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64} }$

$\mathtt{S_6= \dfrac{32+16+8+4+2+1}{64}}$

$\mathbf{S_6= \dfrac{63}{64}}$

Therefore, the sixth partial sum $\mathbf{S_6= \dfrac{63}{64}}$

7 0

3 years ago