A television wave has a_____ wavelength than an infrared wave

FIVE TRUE/FALSE please help

marin [14]

Answer:

9. false

10. true

11. false

12. true

13. true

Explanation:

9. a Newton is the SI unit of force.

11. it says energy can't be created or destroyed

8 0

3 years ago

Tornadoes can be identified and tracked using advanced instruments that can detect small changes in wind velocity and air pressu

sdas [7]

C would be the only logical answer if you really think about what it’s saying about the instrument.

6 0

4 years ago

Which of the following correctly labels the solute and solvent in a solution of ocean water?

DanielleElmas [232]

Hello there!

The solute is salt, and the solvent is water. So the answer is #1.

PS. Can I have Brainliest?

8 0

3 years ago

A 52 gram sample of an unknown metal requires 714 Joules of energy to heat it from

ratelena [41]

Answer: Approximately $0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}$

===================================================

Work Shown:

We have the following variables

Q = 714 joules = heat required
m = 52 grams = mass
c = specific heat = unknown
$\Delta t$ = 82-30.5 = 51.5 = change in temperature

note: the symbol $\Delta$ is the uppercase Greek letter delta. It represents the difference or change in a value.

Apply those values into the formula below. Solve for c.

$Q = m*c*\Delta t\\\\714 = 52*c*51.5\\\\714 = 52*51.5*c\\\\714 = 2678*c\\\\2678*c = 714\\\\c = \frac{714}{2678}\\\\c \approx 0.26661687826737\\\\c \approx 0.267\\\\$

The specific heat of the unknown metal is roughly $0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}$

3 0

3 years ago

20.1 g of aluminum and 219 g of chlorine gas react until all of the aluminum metal has been converted to AlCl3. The balanced equ

Romashka-Z-Leto [24]

Answer:

The amount of Cl2 gas left , after the reaction goes to completion is : 139.655 grams

Explanation:

Molar mass : It is the mass in grams present in one mole of the substance.

Moles of the substance is calculated by:

$Moles=\frac{Mass}{Molar\ mass}$

$2Al(s)+3Cl_{2}(g)\leftarrow 2AlCl_{3}(g)$

According to this equation:

2 mole of Al = 3 mole of Cl2 = 2 mole of AlCl3

Molar mass of Al = 27.0 g/mol

Mass of Al = 20.1 gram

Moles of Al present in the reaction :

$Moles=\frac{Mass}{Molar\ mass}$

$Moles=\frac{20.1}{26.98}$

Moles of Al = 0.744

Similarly calculate the moles of Cl2

Molar mass of Cl2 = 71.0 g/mol

Mass = 219 gram

$Moles=\frac{Mass}{Molar\ mass}$

$Moles=\frac{219}{70.98}$

Moles of Cl2 = 3.08 moles

According to equation,

2 mole of Al reacts with = 3 mole of Cl2

1 moles of Al reacts with = 3/2 mole of Cl2

0.744 moles of Al reacts with = 3/2(0.744) moles of Cl2

= 1.116 moles of Cl2

But actually present Cl2 = 3.08 moles

Hence Al is the limiting reagent , and Cl2 is the excess reagent.

The whole Aluminium Al get consumed during the reaction.

The amount of Cl2 in excess = Total Cl2 - Cl2 consumed

Cl2 in excess = 3.08 - 1.116 = 1.964 moles

Cl2 in grams = 1.964 x 70.90 = 139.655 grams

6 0

4 years ago