Five moles of sulfur dioxide, soz, would consist of how many molecules? molecules Need Help?
1 answer:
Answer:
3 x 10²⁴ molecules
Explanation:
A mole is just a name that we use to substitute a number, just like a dozen means 12, a mole means 6.022 x 10²³. This gives us the unit conversion of 6.022 x 10²³ molecules SO₂/1 mol SO₂.
Round to the lowest number of significant figures to get 3 x 10²⁴ molecules SO₂
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Answer:
The solution 0.010 M has a higher percent ionization of the acid.
Explanation:
The percent ionization can be found using the following equation:
Since we know the acid concentration in the two cases, we need to find [H₃O⁺].
By using the dissociation of acetic acid in the water we can calculate the concentration of H₃O⁺ in the two cases:
1. Case 1 (0.1 M):
CH₃COOH(aq) + H₂O(l) ⇄ CH₃COO⁻(aq) + H₃O⁺(aq) (1)
0.1 - x x x
(2)
Where:
Ka: is the dissociation constant of acetic acid = 1.7x10⁻⁵.
By solving the above equation for x we have:
x = 1.29x10⁻³ M = [CH₃COO⁻] = [H₃O⁺]
Hence, the percent ionization is:
2. Case 2 (0.01 M):
The dissociation constant from reaction (1) is:
With [CH₃COOH] = 0.01 M
By solving the above equation for x:
x = 4.04x10⁻⁴ M = [CH₃COO⁻] = [H₃O⁺]
Then, the percent ionization for this case is:
As we can see, the solution 0.010 M has a higher percent ionization of the acetic acid.
Therefore, the solution 0.010 M has a higher percent ionization of the acid.
I hope it helps you!
This is an incomplete question, here is a complete question.
For the net reaction: 2AB + 2C → A2 + 2BC, the following slow first steps have been proposed.
(1) AB → A + B
(2) 2C + AB → AC + BC
(3) 2AB → A₂ + 2B
(4) C + AB → BC + A
What rate law is predicted by each of these steps?
Answer : The rate law expression for the following reactions are:
(1)
(2)
(3)
(4)
Explanation :
Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
The general reaction is:
The general rate law expression for the reaction is:
where,
a = order with respect to A
b = order with respect to B
R = rate law
k = rate constant
and
= concentration of A and B reactant
Now we have to determine the rate law for the given reaction.
(1) The balanced equations will be:
In this reaction, is the reactant.
The rate law expression for the reaction is:
(2) The balanced equations will be:
In this reaction, and
are the reactants.
The rate law expression for the reaction is:
(3) The balanced equations will be:
In this reaction, is the reactant.
The rate law expression for the reaction is:
(4) The balanced equations will be:
In this reaction, and
are the reactants.
The rate law expression for the reaction is: