The balanced chemical reaction would be as follows:
<span>5P4O6 +8I2 ---> 4P2I4 +3P4O10
We are given the amount of reactants used for the reaction. We first need to determine the limiting reactant from the given amounts. We do as follows:
8.80 g P4O6 (1 mol / </span><span>219.88 g) = 0.04 mol P4O6
12.37 g I2 ( 1 mol / </span><span>253.809 g ) = 0.05 mol I2
Therefore, the limiting reactant is iodine since less it is being consumed completely in the reaction. We calculate the amount of P2I4 prepared as follows:
0.05 mol I2 ( 4 mol P2I4 / 8 mol I2 ) (</span><span>569.57 g / 1 mol) = 14.24 g P2I4</span>
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First we have to refer
to the reaction between the acid and the base: <span>
H2SO4 + 2 NaHCO3 ---> 2 H2O + 2 CO2 + Na2SO4
From this balanced equation we can see that for every 1 mol
of acid (H2SO4), we need 2 mol of base (NaHCO3) to neutralize it. Given 28 ml
of 5.8 M acid, we need to find out how many mols of acid that is:
<span>28mL * (1L/1000mL) * 5.8 mol/L = 0.1624 mol H2SO4</span></span>
<span>
Since we need 2 mol of base per mol of acid, we need:</span>
<span> 2*0.1624 mol = 0.3248 mol NaHCO3 </span><span>
MolarMass of NaHCO3 is 84.01 g/mol
<span>0.3248 mol*(84.01g/mol) = 27.29 g NaHCO3</span></span>
Not guarenteed the answer, but as the temperature increases, the molecules in the gas move faster, impacting the gas's containor more frequently and exerting a greater force, according to Gay-Lussac's Law. I hope this helps you.
