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Nat2105 [25]
3 years ago
14

What is the length of

Mathematics
1 answer:
Alexxandr [17]3 years ago
3 0

By Applying <em><u>Distance formula</u></em>,

=》

d = \sqrt{(5 - 0) {}^{2}  + ( - 9 - ( - 9)) {}^{2} }

=》

d =   \sqrt{5 {}^{2} }

=》

d =  \sqrt{25}

=》

d = 5 \: units

lenght of line segment is <em>5</em><em> </em><em><u>units</u></em>

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2 years ago
What is the missing number in the list of perfect squares 1,4,9,16,25,36,49,_,81,100,121,144
Yuri [45]

Answer:

64

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3 0
3 years ago
Read 2 more answers
Plz help!! A jar contained 6 red marbles, 10 green marbles, and 8 blue marbles. A marble was selected at random, the color was r
Inessa [10]

Answer:

To calculate the relative frequency, first we need to know what exactly is and how to calculate it.

Relative frequency is the ratio between the absolute frequency (how many repetitions have a specific outcome) and the total outcomes. Also, this type of frequency is used to show the representation that some data have over the whole distribution.

So, in this case, we need to just divide 13, which belongs to red marble's results, to 60 which is the total outcomes, as it's presented:

         13redmarble                                                                                                                       Fr = -------------------------

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Normally, relative frequency is shown as a percentage multiplying this result by 100. Therefore, 22% is the approximate percentage of the relative frequency, which means that 22% is the representation of red marbles outcomes of the whole distribution, or we can say it as a probability: there's 22% of chances when someone extract a marble, it will be red.

3 0
2 years ago
Is the answer a,b,c or d​
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5 0
3 years ago
one number is 1 more than 2 times another. if their sum is increased by sevan, the result is twenty six
Lady bird [3.3K]

the numbers are 6 and 13

let x be one of the numbers then the other is 2x + 1

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divide both sides by 3

x = \frac{18}{3} = 6

the numbers are 6 and (2 × 6) + 1 = 12 + 1 = 13


7 0
2 years ago
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