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eimsori [14]
2 years ago
13

The area of a circle is 95.75cm2. Find the length of the radius rounded to 2 DP.

Mathematics
1 answer:
notka56 [123]2 years ago
4 0

Answer:

5.52 cm

Step-by-step explanation:

area of circle =pi r^2

r=square root (95.75/pi)

=5.52

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how many ounces of pure water must be added to 50 ounces of a 15% saline solution to make a saline solution that is 10% salt
anygoal [31]

50 ounces of 15% saline solution contains 0.15*50 = 7.5 ounces of salt.

Let x be the amount of pure water you add to this solution. Then you end up with (x + 50) ounces of this new solution. The amount of salt stays the same.

You want the new solution to have a concentration of 10%. This means you need

7.5 / (x + 50) = 0.1

==>  7.5 = 0.1(x + 50)

==>  7.5 = 0.1x + 5

==>  2.5 = 0.1x

==>  2.5/0.1 = 0.1x/0.1

==>  x = 25

7 0
3 years ago
In two or more complete sentences, explain how to find the average rate of change of a function.
Anon25 [30]
To find the average rate of change, evaluate the function at the given points.
Evaluate the difference of the function at the given points.
Divide the difference of the function at the given points with the difference of the given points.
3 0
2 years ago
Which statement describes the solutions of the equation? 4x/3x+1 = x/2x+10
stiks02 [169]

Answer:

<h3> The equation has one valid solution and no extraneous of solutions.</h3>

Step-by-step explanation:

Given the expression;

4x/3x+1 = x/2x+10

We are to get the nature of the value of x

Cross multiply;

x(3x+1) = 4x(2x+10)

3x²+x = 8x²+40x

Collect like terms;

3x²-8x² + x - 40x = 0

-5x²+x -40x = 0

-5x²-39x = 0

-5x² = 39x

-5x = 39

x = -39/5

<em>Since we have just one value of x hence, the equation has one valid solution and no extraneous of solutions.</em>

<em></em>

<em></em>

4 0
2 years ago
Read 2 more answers
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Ksju [112]
Is this math? or English
4 0
2 years ago
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
borishaifa [10]

Answer:

the concentration at 10 minutes= 0.4+0.0133= 0.4133%

Step-by-step explanation:

Air containing 0.04% carbon dioxide

V, volume of room is 6000 ft3.

Q, rate of air 2000 ft3/min,

initial concentration of 0.4% carbon dioxide,

determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes?

firstly, we find the time taken for air to completely filled the room

Q = V/t

t = V/Q = 6000/2000 = 3min

so, its take 3mins for air to be completely filled in the room and for exhaust air to move out.

there is  an initial concentration of 0.4% carbon dioxide, and the air pump in is 0.04%.

therefore,

3mins = 0.04% of CO2

3*60 =180sec = 0.04%

1sec = 0.04/180 = 0.00022%/sec

so at any time the concentration of CO2 is 0.4 + 0.00022 =0.40022%/sec

What is the concentration at 10 minute

the concentration at 10minutes = the concentration for 1minute because at every minutes, the concentration moves in is moves out. = concentration for 2000ft3.

for 0.04% = 6000ft3

   ?          = 2000ft3

              = 2000* 0.04)/6000 =0.0133%

the concentration at 10 minutes= 0.4+0.0133= 0.4133%

4 0
3 years ago
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