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3 years ago

The area of a circle is 95.75cm2. Find the length of the radius rounded to 2 DP.

Mathematics

1 answer:

notka56 [123]3 years ago

4 0

Answer:

5.52 cm

Step-by-step explanation:

area of circle =pi r^2

r=square root (95.75/pi)

=5.52

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Determine whether the given value is a solution of the equation. 36 = k 6 ; k = 6 6 a solution of 36 = k 6 .

Mila [183]

Answer:

Yes: the variable K would equal "6"

Step-by-step explanation:

After you set you equation up, you have to isolate the given variable. To do that you have to do the recipriocal (6k-multiplying) which would be division. You would divide k = 36 ÷ 6 . that isolates the variable ,which you would then solve. k = 6 .

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3 years ago

A performer expects to sell 5,000 tickets for an upcoming concert. They want to make a total of $311, 000 in sales from these ti

Annette [7]

The price of one ticket is $ 62.2

<h3><u>Solution:</u></h3>

Given that a performer expects to sell 5000 tickets for an upcoming event

They want to make a total of $ 311, 000 in sales from these tickets

<em><u>To find: price of one ticket</u></em>

Let us assume that all tickets have the same price

Let "a" be the price of one ticket

So the total sales price of $ 311, 000 is obtained from product of 5000 tickets and price of one ticket

$\text {total sales price }=5000 \times \text { price of one ticket }$

$311000 = 5000 \times a\\\\a = \frac{311000}{5000}\\\\a = 62.2$

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3 years ago

What numbers are zeros of g(x) = x^2 - 2x - 4? take your time if you need to!

ipn [44]

Answer:

$x = 1 + \sqrt5, x = 1 - \sqrt5$

Step-by-step explanation:

Hello!

We can solve the quadratic by using the quadratic formula.

Standard form of a quadratic: $ax^2 + bx + c = 0$

Quadratic Formula: $x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$

Given our Equation: $g(x) = x^2 - 2x - 4$

a = 1
b = -2
c = -4

Plug the values into the equation and solve.

<h3>Solve</h3>

$x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$
$x = \frac{-(-2)\pm\sqrt{(-2)^2 - 4(1)(-4)}}{2(1)}$
$x = \frac{2\pm\sqrt{4 +16}}{2}$
$x = \frac{2\pm\sqrt{20}}{2}$
$x = \frac{2\pm\sqrt{4 * 5}}{2}$
$x = \frac{2\pm(\sqrt4 * \sqrt5)}{2}$
$x = \frac{2\pm2\sqrt5}{2}$
$x = 1 + \sqrt5, x = 1 - \sqrt5$

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2 years ago

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My name is Ann [436]

The answer would be b=0

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2 years ago

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