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GREYUIT [131]
2 years ago
15

The Hurry-Mart convenient store is re-stocking their shelves. They always stock the m&m to Hershey bars at a ratio of 10 to

8. How many Hershey bars do they need if they have 15 bags of m&ms ?
Mathematics
1 answer:
castortr0y [4]2 years ago
8 0

Answer:

12 Hershey bars

Step-by-step explanation:

if its 10 to 8 and you have 15 m&m then you would have to do the 10 which you would have to put 8 then 5 is half of 10 so you would just half 8 which is 4 so 8+4+12. 12 Hershey bars needed to restock the shelf.

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jonny [76]

<u>Question 1</u>

If we let FE=x, then DE=x-5.

Also, as \overline{DF} bisects \overline{BC}, this means BE=EC=6.

Thus, by the intersecting chords theorem,

6(6)=x(x-5)\\\\36=x^2 - 5x\\\\x^2 - 5x-36=0\\\\(x-9)(x+4)=0\\\\x=-4, 9

However, as distance must be positive, we only consider the positive case, meaning FE=9

<u>Question 2</u>

If we let CE=x, then because AB bisects CD, CE=ED=x.

We also know that since FB=17, the radius of the circle is 17. So, this means that the diameter is 34, and as AE=2, thus means EB=32.

By the intersecting chords theorem,

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However, as distance must be positive, we only consider the positive case, meaning CE=8

4 0
2 years ago
Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 5% of all
Gnom [1K]

Answer:

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

Step-by-step explanation:

For each visitor of the website, there are only two possible outcomes. Either they are looking for the website, or they are not. The probability of a customer being looking for the website is independent of other customers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% of all visitors to the website are looking for other websites.

So 100 - 5 = 95% are looking for the website, which means that p = 0.95

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This is P(X = 2) when n = 4. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = x) = C_{4,2}.(0.95)^{2}.(0.05)^{2} = 0.0135

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

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