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boyakko [2]
3 years ago
6

estimate each sum or difference to the nearest whole numbers. then calculate the exact sum or difference....58.02-15.27-3.76

Mathematics
1 answer:
omeli [17]3 years ago
8 0

Answer:

38.99

Step-by-step explanation:

58.02 - 15.27 = 42.75

42.75 - 3.76 = 38.99

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Lines DE and AB intersect at point C.
alexandr402 [8]

Answer:

25

Step-by-step explanation:

2x+2+5x+3=180 (angles on a straight line)

7x+5=180

7x=180-5

7x=175

x=25 (dividing both sides by 7)

3 0
3 years ago
B is the midpoint of AC. AB = 2x+12 and BC = 5x + 10. Find AC
3241004551 [841]

Answer:

x=6

Step-by-step explanation:

/AB/=2x+12

/BC/=5x+10

3x+2=5x-10 subtract 2 from both sides

3x=5x-12 subtract 5x from both sides

-2x=-12 divide both sides by -2x

x =6

5 0
2 years ago
What is x<br> 7x-21=4x-36
soldier1979 [14.2K]

Answer:

x = -5

Step-by-step explanation:

5 0
3 years ago
Jasmine had a carrot cake with cream cheese frosting for her birthday .she and her friend each ate 1/4 of the cake and jasmine's
zloy xaker [14]
Hey there!

To solve this problem, you first would need to solve for how much of the cake is left after Jasmine, her friend, and Jasmine's brother got their slices. Then, you would need to split the remaining amount in half to get the answer of what each parent ate. We would need to make all of the denominators the same, so let's make all of the fractions out of 12, a common denominator of 3 and 4. 

\frac{12}{12} - \frac{1}{4} - \frac{1}{4} - \frac{1}{3}
\frac{12}{12} - \frac{3}{12} - \frac{3}{12} - \frac{4}{12}
\frac{12}{12} - \frac{10}{12} = \frac{2}{12}

It can then be concluded that each parent ate \frac{1}{12} of the cake, since there was \frac{2}{12} remaining. 

You can check this answer by adding up all of the parts we used in this problem:

\frac{3}{12} + \frac{3}{12} + \frac{4}{12} +  \frac{1}{12} +  \frac{1}{12} = \frac{12}{12}

Hope this helped you out! :-)
3 0
3 years ago
If 2.5 is a root of the equation 2x^2+5x−q=0, what are the possible values of q?
bulgar [2K]

Answer:

q = -2510 +5 = \pm \sqrt{5^2-4*2*q} \\ 225 = 25-8q \\\\8q = -200 \rightarrow q = -\frac {200}8 = -25

Step-by-step explanation:

Grab the generic solution of the equation. \frac 52 = \frac{-5 \pm \sqrt{5^2-4*2*q}}{2*2}. Let's isolate the radical, and square both sides.10 +5 = \pm \sqrt{5^2-4*2*q} \\ 225 = 25-8q \\\\8q = -200 \rightarrow q = -\frac {200}8 = -25

4 0
3 years ago
Read 2 more answers
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