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Serggg [28]
3 years ago
14

A G.P has its 3rd term and 7th term as 45 and 3645 respectively. what is the product of its 2nd and 4th

Mathematics
1 answer:
Ede4ka [16]3 years ago
3 0

Answer:

2,025

Step-by-step explanation:

Given:

Third term ar² = 45

Seventh term ar⁶ = 3,645

Find:

ar x ar³

Computation:

From 7th term / 3rd term

ar⁶ / ar² = 3,645 / 45

r⁴ = 81

r = 3

So,

ar² = 45

a(3)² = 45

a = 5

So,

ar x ar³

(5)(3) x (5)(3)³

2,025

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Natasha_Volkova [10]
Answer=140 fish

200 gallons of water in the first aquarium.

200 gallons of water in the second aquarium.

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cross multiply
10x=1000
divide both sides by 10
x=100 small fish

The first aquarium has 100 small fish.

The second aquarium holds large fish.

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cross multiply
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The second aquarium has 40 large fish.

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7 0
3 years ago
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The line plot shows the weights of packages of meat available at a grocery store. The 3 lightest packages cost $4.40 per pound.
Mnenie [13.5K]

Answer:

$42.40

Step-by-step explanation:

The horizontal axis is in fractions.

The three lightest are two  \frac{5}{8} pounds & one  \frac{6}{8} pounds. Each cost $4.40 per pound.

So cost = 4.40(5/8+5/8+6/8) = $8.8

Remaining costs 4.80 per pound. We add up the remaining and multiply by 4.80 to get their cost.

cost = 4.80(1+1\frac{1}{8}+1\frac{1}{8}+1\frac{1}{8}+1\frac{2}{8}+1\frac{3}{8})=33.6

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I need help getting the answer for the 1st question
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If we have two similar triangles:
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Triangle 2 (base 2, height 2)
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Data:
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height 1= 1 m
base 2= 8 m
height 2=x

We calculate the height of the tower:
base 1 /height 1=base 2 /height 2
0.2 m / 1m=8 m / x
x=(8 m * 1 m) / 0.2 m
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On his outward journey, Ali travelled at a speed of s km/h for 2.5 hours. On his return journey, he increased his speed by 4 km/
den301095 [7]

Answer:

3.08 km/h.

Step-by-step explanation:

We know that,

Speed=\dfrac{Distance}{Time}

Ali traveled at a speed of s km/h for 2.5 hours.

Let d be the distance and t be the time.

2.5=\dfrac{d}{t}

2.5t=d      ...(1)

On his return journey, he increased his speed by 4 km/h and saved 15 minutes. So, distance is d and times is t-15.

4=\dfrac{d}{t-15}

4(t-15)=d      ...(2)

From (1) and (2), we get

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t=40

Put t=40 in (1).

d=2.5(40)=100

So, t=40 and d=100.

Now,

Total distance = d + d = 100 + 100 = 200

Total time = t + t - 15 = 40 + 40 - 15 = 65

So, the average speed is

\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}

\text{Average speed}=\dfrac{200}{65}

\text{Average speed}\approx 3.08

Therefore, the average speed is 3.08 km/h.

3 0
3 years ago
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