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emmainna [20.7K]
3 years ago
13

Please help! Thank you!

Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0

Answer:

(-16,17)

Step-by-step explanation:

The answer for the and point D is negative 16, 17. how you will solve this is you would take them in point and the endpoint c. to find that x of D you will do negative 4 minus 8 this equals negative 12. what you will do next is you will take the negative 12 and added to -4. this is how you get negative 16. you will then find the y of D. to do this you will take negative 7 and subtract 5. this equals negative 12. you will then take the midpoint and do 5 + 12. this equals 17. Hope this helps!

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Which inequality represents the values of that ensure triangle exists? a triangle with these side lengths: AC = 18 units, BC = 6
erastovalidia [21]

AC = 18

BC = 6x

AB = 2x + 4


Write and solve:

18 + 6x + 2x + 4

18 + 8x + 4 = 180


You can solve further:

18 + 8x = 176

8x = 158

x = 19 & 3/4


Not 100% sure what the question is asking, but hopefully this helps.

5 0
3 years ago
(2, 7) and (-6, -2) find the distance between each pair of points
yaroslaw [1]

Answer:

\sqrt{145}

Step-by-step explanation:

Hi there!

We are given the points (2, 7) and (-6, -2). We want to find the distance between them. To do that, we can use the distance formula

The distance formula is given as \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}, where (x_1, y_1) and (x_2, y_2) are points

We have 2 points, which is what we need to find the distance, but let's label their values to avoid any confusion

x_1=2\\y_1=7\\x_2=-6\\y_2=-2

Now substitute those values into the formula:

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\sqrt{(-6-2)^2+(-2-7)^2}

Simplify the values under the radical:

\sqrt{(-8)^2+(-9)^2}

Raise to the second power:

\sqrt{64+81}

Add the numbers under the radical together

\sqrt{145}

The answer can be left as that, as the radical cannot be simplified.

Hope this helps!

7 0
3 years ago
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Answer:

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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:84

7 X 12 = 84

Step-by-step explanation:

3 0
3 years ago
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