All categories

2 years ago

Please help! Thank you!

Mathematics

1 answer:

Dafna1 [17]2 years ago

6 0

Answer:

(-16,17)

Step-by-step explanation:

The answer for the and point D is negative 16, 17. how you will solve this is you would take them in point and the endpoint c. to find that x of D you will do negative 4 minus 8 this equals negative 12. what you will do next is you will take the negative 12 and added to -4. this is how you get negative 16. you will then find the y of D. to do this you will take negative 7 and subtract 5. this equals negative 12. you will then take the midpoint and do 5 + 12. this equals 17. Hope this helps!

You might be interested in

A doctor told his patient to drink 3 full cups and 1/2 of a cup of medicine over a week.

Nadya [2.5K]

Answer:

The patient is going to drink 14 pints of medicine over a week

Step-by-step explanation:

1. Let's review all the information provided to answer the question correctly:

Amount of medicine the doctor told his patient to drink over a week = 3 1/2 cups

1 full cup = 4 pints

2. How much is the patient going to drink over the week?

For answering this question, we multiply this way:

3 1/2 = 3.5

3.5 * 4 = 14

The patient is going to drink 14 pints of medicine over a week

8 0

3 years ago

HELPPPPPPPPPPPPPP Solve for x and y

frosja888 [35]

Answer:

x = 0, y = -1

Step-by-step explanation:

10x = 5y + 5

y = 2x - 1

======================

10x = 5(2x - 1) + 5

10x = 10x - 5 + 5

x = 0

======================

y = 2x - 1

y = -1

7 0

2 years ago

Make sure all solutions are in lowest terms. 5/6 • 1/3

stiks02 [169]

1/3=2/6
5/6x2/6= 10/36
10/36 simplified is 5/18

3 0

2 years ago

Write another expression equivalent to 2(x + 3) please answer i will make you brainliest

inna [77]

Answer:

2x + 6

Step-by-step explanation:

distribution

plz mark branliest

6 0

3 years ago

Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)

babunello [35]

$\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k$

We want to find $f(x,y,z)$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=x^2+y$

$\dfrac{\partial f}{\partial y}=y^2+x$

$\dfrac{\partial f}{\partial z}=ze^z$

Integrating both sides of the latter equation with respect to $z$ tells us

$f(x,y,z)=e^z(z-1)+g(x,y)$

and differentiating with respect to $x$ gives

$x^2+y=\dfrac{\partial g}{\partial x}$

Integrating both sides with respect to $x$ gives

$g(x,y)=\dfrac{x^3}3+xy+h(y)$

Then

$f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)$

and differentiating both sides with respect to $y$ gives

$y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C$

So the scalar potential function is

$\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}$

By the fundamental theorem of calculus, the work done by $\vec F$ along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it $L$ ) in part (a) is

$\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}$

and $\vec F$ does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them $L_1$ and $L_2$ ) of the given path. Using the fundamental theorem makes this trivial:

$\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3$

$\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4$

8 0

3 years ago