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weeeeeb [17]
3 years ago
14

5 lbs 4 oz - 12 oz =?​

Mathematics
1 answer:
vaieri [72.5K]3 years ago
7 0

Answer:

4lbs 8oz

Step-by-step explanation:

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A cyclist travels 4miles in 15 minutes. What is her average speed in mph?
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5

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Evaluate each expression by (1) using the Distributive Property and (2) evaluating inside the parentheses first.
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Answer:

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Step-by-step explanation:

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2 years ago
HELP ME ASAP for 37 points!! which expression is equivalent to 14.5d+8.5-1/2d+1/2+2.5d
lina2011 [118]

Equivalent expressions are expressions with equal values

The equivalent expression is 16.5d+9

<h3>How to determine the equivalent expression</h3>

The expression is given as:

14.5d+8.5-1/2d+1/2+2.5d

Express the fractions as decimals

14.5d+8.5-0.5d+0.5+2.5d

Collect like terms

14.5d-0.5d+2.5d+8.5+0.5

Evaluate the like terms

16.5d+9

Hence, the equivalent expression is 16.5d+9

Read more about equivalent expressions at:

brainly.com/question/2972832

7 0
2 years ago
Put together, Dulcina and Tremaine have 129 total matchbooks. Tremaine's collection has 39 fewer matchbooks in it than Dulcina's
Anit [1.1K]

Answer:

Let the Dulcina's collection be 'x'

Let the Tremaine collection be 'x-39'

x + x - 39 =129

2x = 129 +39

2x = 168

x = 168/2

x = 84

Dulcina's collection = x = 84

Tremaine's collection = x - 39 = 84 - 39 = 45

7 0
3 years ago
Sviatoslav solved the quadratic equation x^2-x-1=0 by completing the square. In the process, he came up with the equivalent equa
zimovet [89]

Answer:

x=\frac{1+\sqrt5}{2} and  x=\frac{1-\sqrt5}{2}

and b=\frac{5}{4}

Step-by-step explanation:

We are given that a quadratic equation

x^2-x-1=0

We have to solve the equation by completing square and find the value of b.

(x)^2-2\times x\times \frac{1}{2}+(\frac{1}{2})^2-(\frac{1}{2})^2-1=0

(x-\frac{1}{2})^2-\frac{1}{4}-1=0

(x-\frac{1}{2})^2-\frac{1-4}{4}=0

(x-\frac{1}{2})-\frac{5}{4}=0

(x-\frac{1}{2})^2-(\frac{\sqrt5}{2})^2=0

(x-\frac{1}{2})^2=(\frac{\sqrt5}{2})^2

x-\frac{1}{2}=\frac{\sqrt5}{2} and x-\frac{1}{2}=-\frac{\sqrt5}{2}

x=\frac{\sqrt5}{2}+\frac{1}{2}=\frac{1+\sqrt5}{2}

And x=\frac{1}{2}-\frac{\sqrt5}{2}=\frac{1-\sqrt5}{2}

Therefore,x=\frac{1+\sqrt5}{2} and  x=\frac{1-\sqrt5}{2}

and b=\frac{5}{4}

6 0
3 years ago
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