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12345 [234]
3 years ago
11

To approach the runway, a pilot of a small plane must begin at 6 degrees,descent starting from a height of 1905 feet above the g

round. To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach

Mathematics
1 answer:
koban [17]3 years ago
6 0

Answer:

C. 3.5 mi

Step-by-step explanation:

Reference angle = angle of elevation

Angle of elevation = angle of depression = 6° (alternate angle theorem)

Hypotenuse = x

Opposite = 1905 ft

Apply trigonometric function SOH:

Sin 6° = Opp/Hyp

Sin 6° = 1905/x

x * Sin 6° = 1905

x = 1905/Sin 6°

x = 18,224.7 ft

Convert form feet to miles

1 mi = 5,280 ft

Therefore,

18,224.7 = 18,224.7/5,280

= 3.45164773 mi

≈ 3.5 mi (nearest mile)

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Answer:

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Answer:

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Step-by-step explanation:

Taking Laplace of the given differential equation:

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Put t = 0 in equation (D)

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Now take derivative of (D) with respect to "t", we get:

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